I have a Char(15)
field, in this field I have the data below:
94342KMR
947JCP
7048MYC
I need to break down this, I need to get the last RIGHT 3 characters and I need to get whatever is to the LEFT. My issue is that the code on the LEFT is not always the same length as you can see.
How can I accomplish this in SQL?
Thank you
SELECT RIGHT(RTRIM(column), 3),
LEFT(column, LEN(column) - 3)
FROM table
Use RIGHT
w/ RTRIM
(to avoid complications with a fixed-length column), and LEFT
coupled with LEN
(to only grab what you need, exempt of the last 3 characters).
if there's ever a situation where the length is <= 3, then you're probably going to have to use a CASE
statement so the LEFT
call doesn't get greedy.
You can use RTRIM
or cast your value to VARCHAR
:
SELECT RIGHT(RTRIM(Field),3), LEFT(Field,LEN(Field)-3)
Or
SELECT RIGHT(CAST(Field AS VARCHAR(15)),3), LEFT(Field,LEN(Field)-3)
Here an alternative using SUBSTRING
SELECT
SUBSTRING([Field], LEN([Field]) - 2, 3) [Right3],
SUBSTRING([Field], 0, LEN([Field]) - 2) [TheRest]
FROM
[Fields]
with fiddle
select right(rtrim('94342KMR'),3)
This will fetch the last 3 right string.
select substring(rtrim('94342KMR'),1,len('94342KMR')-3)
This will fetch the remaining Characters.