T-SQL How to select only Second row from a table?

问题:

I have a table and I need to retrieve the ID of the Second row. How to achieve that ?

By Top 2 I select the two first rows, but I need only the second row

回答1:

Assuming SQL Server 2005+ an example of how to get just the second row (which I think you may be asking - and is the reason why top won't work for you?)

set statistics io on

;with cte as
(
select * ,
ROW_NUMBER() over (order by number) as rn
from master.dbo.spt_values
) 
select * from cte where rn=2

/*Just to add in what I was running RE: Comments*/
;with cte as
(
select top 2 * ,
ROW_NUMBER() over (order by number) as rn
from master.dbo.spt_values
) 
select * from cte where rn=2

回答2:

In SQL Server 2012+, you can use OFFSET...FETCH:

SELECT
   <column(s)>
FROM
   <table(s)>
ORDER BY
   <sort column(s)>
OFFSET 1 ROWS   -- Skip this number of rows
FETCH NEXT 1 ROW ONLY;  -- Return this number of rows

回答3:

Use ROW_NUMBER() to number the rows, but use TOP to only process the first two.

try this:

DECLARE @YourTable table (YourColumn int)
INSERT @YourTable VALUES (5)
INSERT @YourTable VALUES (7)
INSERT @YourTable VALUES (9)
INSERT @YourTable VALUES (17)
INSERT @YourTable VALUES (25)

;WITH YourCTE AS
(
SELECT TOP 2
    *, ROW_NUMBER() OVER(ORDER BY YourColumn) AS RowNumber
    FROM @YourTable
) 
SELECT * FROM YourCTE WHERE RowNumber=2

OUTPUT:

YourColumn  RowNumber
----------- --------------------
7           2

(1 row(s) affected)

回答4:

No need of row number functions if field ID is unique.

SELECT TOP 1 * FROM 
                   ( SELECT TOP 2 * 
                     FROM yourTable
                     ORDER BY ID
                   ) z
ORDER BY ID DESC

回答5:

I'm guessing you're using SQL 2005 or greater. The 2nd line selects the top 2 rows and by using 'ORDER BY ROW_COUNT DESC", the 2nd row is arranged as being first, then it is selected using TOP 1

SELECT TOP 1 COLUMN1, COLUMN2 from (
SELECT TOP 2 COLUMN1, COLUMN2 FROM Table) ORDER BY ROW_NUMBER DESC 

回答6:

with T1 as
(
select row_number() over(order by ID) rownum, T2.ID
from Table2 T2
)
select ID from T1 where rownum=2

回答7:

Select top 2 [id] from table Order by [id] desc should give you want you the latest two rows added.

However, you will have to pay particular attention to the order by clause as that will determine the 1st and 2nd row returned.

If the query was to be changed like this:

Select top 2 [id] from table Order by ModifiedDate desc

You could get two different rows. You will have to decide which column to use in your order by statement.

回答8:

Certainly TOP will surfice if you simply want the TOP 2, but if you need them individually so that you can do something with those values then use the ROW_NUMBER which will give you more control over the rows you want to select

ps. I did this as i'm not sure if the OP is after a simple TOP 2 in a select. (I may be wrong!)

-- Get first row, same as TOP 1
SELECT [Id] FROM 
(
    SELECT [Id], ROW_NUMBER() OVER (ORDER BY [Id]) AS Rownumber
    FROM table
) results
WHERE results.Rownumber = 1

-- Get second row only
SELECT [Id] FROM 
(
    SELECT [Id], ROW_NUMBER() OVER (ORDER BY [Id]) AS Rownumber
    FROM table
) results
WHERE results.Rownumber = 2

回答9:

Use TOP 2 in the SELECT to get the desired number of rows in output. This would return in the sequence the data was created. If you have a date option you could order by the date along with TOP n Clause.

To get the top 2 rows;

SELECT TOP 2 [Id] FROM table 

To get the top 2 rows order by some field

SELECT TOP 2[ID] FROM table ORDER BY <YourColumn> ASC/DESC

To Get only 2nd Row;

WITH Resulttable AS 
( 
SELECT TOP 2 
    *, ROW_NUMBER() OVER(ORDER BY YourColumn) AS RowNumber 
    FROM @Table 
)  
SELECT * FROM Resultstable WHERE RowNumber=2

回答10:

You can use select top 2 Id from yourtable.

回答11:

This is also useful:

SELECT
t.*
FROM
(
SELECT
e1.*,
row_number() OVER (
ORDER BY e1.Rate DESC) AS _Rank
FROM
HumanResources.EmployeePayHistory AS e1
) AS t
WHERE
t._Rank = 2

回答12:

This is defiantly working

SELECT * FROM 
(
SELECT top 3 *, ROW_NUMBER() OVER (ORDER BY [newsid] desc) AS Rownumber
FROM news where (news_type in(2,12))
) results
WHERE results.Rownumber = 1

//news table name and newsid column name

回答13:

you can use OFFSET and FETCH NEXT

SELECT id
FROM tablename
ORDER BY column
OFFSET 1 ROWS
FETCH NEXT 1 ROWS ONLY;

NOTE:

OFFSET can only be used with ORDER BY clause. It cannot be used on its own.

OFFSET value must be greater than or equal to zero. It cannot be negative, else return error.

The OFFSET argument is used to identify the starting point to return rows from a result set. Basically, it exclude the first set of records.

The FETCH argument is used to return a set of number of rows. FETCH can’t be used itself, it is used in conjuction with OFFSET.

回答14:

SELECT TOP 2 [Id] FROM table

回答15:

Select Top 1 * from ( select Top 2 * from YourTableName)YourTableName order by yourtableColumnName

回答16:

select * from (select ROW_NUMBER() OVER (ORDER BY Column_Name) as ROWNO,* from Table_Name) Table_Name where ROWNO = 2