Best way to get query string from a URL in python?

问题:

I need to get the query string from this URL https://stackoverflow.com/questions/ask?next=1&value=3 and I don't want to use request.META. I have figured out that there are two more ways to get the query string:

1. Using urlparse urlparse.urlparse(url).query

2. Using url encode Use urlencode and pass the request.GET params dictionary into it to get the string representation.

So which way is better? My colleagues prefer urlencode but have not provided a satisfying explanation. They claim that urlparse calls urlencode internally which is something I'm not sure about since urlencode lives in the urllib module.

回答1:

You can make Query string using GET parameters like this

request.GET.urlencode()

This does not include the ? prefix, and it may not return the keys in the same order as in the original request.

回答2:

Third option:

>>> from urlparse import urlparse, parse_qs
>>> url = 'http://something.com?blah=1&x=2'
>>> urlparse(url).query
'blah=1&x=2'
>>> parse_qs(urlparse(url).query)
{'blah': ['1'], 'x': ['2']}

In Python 3+ this is available as:

from urllib.parse import parse_qs

Documentation for urllib.parse

回答3:

I prefer using

request.META['QUERY_STRING']

From docs:

https://docs.djangoproject.com/en/stable/ref/request-response/#django.http.HttpRequest.META

This does not include the ? prefix.

回答4:

you can also use request.arg also

if 'next' in request.arg and 'values' in request.arg:
    next = request.arg.get('next', '')
    value = request.arg.get('value', '')