Python >=3.5: Checking type annotation at runtime

问题:

Does the typing module (or any other module) exhibit an API to typecheck a variable at runtime, similar to isinstance() but understanding the type classes defined in typing?

I'd like to be to run something akin to:

from typing import List
assert isinstance([1, 'bob'], List[int]), 'Wrong type'

回答1:

There is no such function in the typing module, and most likely there won't ever be.

Checking whether an object is an instance of a class - which only means "this object was created by the class' constructor" - is a simple matter of testing some tagging.

However, checking whether an object is an "instance" of a type is not necessarily decidable:

assert isinstance(foo, Callable[[int], str]), 'Wrong type'

Although it is easy to inspect the typing annotations of foo (assuming it's not a lambda), checking whether it complies to them is generally undecidable, by Rice's theorem.

Even with simpler types, such as List[int] the test will easily become far too inefficient to be used for anything but the smallest toy examples.

xs = set(range(10000))
xs.add("a")
xs.pop()
assert isinstance(xs, Set[int]), 'Wrong type'

---

The trick that allows type checker to perform this operation in a relatively efficient way, is to be conservative: the type checker tries to prove that foo always return int. If it fails, it rejects the program, even though the program may be valid, i.e. this function is likely to be rejected, although it is perfectly safe:

def foo() -> int:
    if "a".startswith("a"):
        return 1
    return "x"