Android Email Validation on EditText

问题:

hello everyone i have one edittext and i would to to write email validation in my Editttext this is a xml code

<EditText
        android:id="@+id/mail"
        android:layout_width="match_parent"
        android:layout_height="48dp"
        android:layout_alignLeft="@+id/phone"
        android:layout_below="@+id/phone"
        android:layout_marginRight="33dp"
        android:layout_marginTop="10dp"
        android:background="@drawable/edit_background"
        android:ems="10"
        android:hint="E-Mail"
        android:inputType="textEmailAddress"
        android:paddingLeft="20dp"
        android:textColor="#7e7e7e"
        android:textColorHint="#7e7e7e" >
    </EditText>

and this is a java code

emailInput = mail.getText().toString().trim();

    emailPattern = "^[_A-Za-z0-9-]+(\\.[_A-Za-z0-9-]+)*@[A-Za-z0-9]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";


    if (emailInput.matches(emailPattern)) {
            Toast.makeText(getActivity(), "valid email address",
                    Toast.LENGTH_SHORT).show();


        } else {
            Toast.makeText(getActivity(), "Invalid email address",
                    Toast.LENGTH_SHORT).show();
            mail.setBackgroundResource(R.drawable.edit_red_line);
        }

i can't validation.the toast message is always "Invalid email address" what am i doing wrong? if anyone knows solution please help me

回答1:

Why not use:

public final static boolean isValidEmail(CharSequence target) {
  return !TextUtils.isEmpty(target) && android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}

As suggested here.

回答2:

I am posting very simple and easy answer of email validation without using any string pattern.

1.Set on click listener on button....

 button_resetPassword.setOnClickListener(new View.OnClickListener()
    {
        @Override
        public void onClick(View v)
        {
            CharSequence temp_emilID=username.getText().toString();//here username is the your edittext object...
            if(!isValidEmail(temp_emilID))
            {
                username.requestFocus();
                username.setError("Enter Correct Mail_ID ..!!");
                     or
                Toast.makeText(getApplicationContext(), "Enter Correct Mail_ID", Toast.LENGTH_SHORT).show();

            }
            else
           {
              correctMail.. 
             //Your action...

           }

         });

2.call the isValidEmail() i.e..

   public final static boolean isValidEmail(CharSequence target)
   {
    if (TextUtils.isEmpty(target))
    {
        return false;
    } else {
        return android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
    }
 }

I hope it will helpful for you...

回答3:

Android Email Validation Simplest way

   String validemail= "[a-zA-Z0-9\\+\\.\\_\\%\\-\\+]{1,256}" +

                        "\\@" +

                        "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,64}" +

                        "(" +

                        "\\." +

                        "[a-zA-Z0-9][a-zA-Z0-9\\-]{0,25}" +

                        ")+";

               String emal=email.getText().toString();

                Matcher matcherObj = Pattern.compile(validemail).matcher(emal);



                        if (matcherObj.matches()) {

                               Toast.makeText(getApplicationContext(), "enter 

all details", Toast.LENGTH_SHORT).show();

                        }

                        else 
{
                            Toast.makeText(getApplicationContext(),"please enter 

valid email",Toast.LENGTH_SHORT).show();

                        }

回答4:

Try following code:

public final static boolean isValidEmail(CharSequence target) {
    return !TextUtils.isEmpty(target) && android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches();
}

This works fine.

回答5:

here is a whole code for login validations......

public class LoginActivity extends AppCompatActivity {
private static final String TAG = "LoginActivity";
private static final int REQUEST_SIGNUP = 0;

@Bind(R.id.input_email) EditText _emailText;
@Bind(R.id.input_password) EditText _passwordText;
@Bind(R.id.btn_login) Button _loginButton;
@Bind(R.id.link_signup) TextView _signupLink;

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_login);
    ButterKnife.bind(this);

    _loginButton.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            login();
        }
    });

    _signupLink.setOnClickListener(new View.OnClickListener() {

        @Override
        public void onClick(View v) {
            // Start the Signup activity
            Intent intent = new Intent(getApplicationContext(), SignupActivity.class);
            startActivityForResult(intent, REQUEST_SIGNUP);
            finish();
            overridePendingTransition(R.anim.push_left_in, R.anim.push_left_out);
        }
    });
}

public void login() {
    Log.d(TAG, "Login");

    if (!validate()) {
        onLoginFailed();
        return;
    }

    _loginButton.setEnabled(false);

    final ProgressDialog progressDialog = new ProgressDialog(LoginActivity.this,
            R.style.AppTheme_Dark_Dialog);
    progressDialog.setIndeterminate(true);
    progressDialog.setMessage("Authenticating...");
    progressDialog.show();

    String email = _emailText.getText().toString();
    String password = _passwordText.getText().toString();

    // TODO: Implement your own authentication logic here.

    new android.os.Handler().postDelayed(
            new Runnable() {
                public void run() {
                    // On complete call either onLoginSuccess or onLoginFailed
                    onLoginSuccess();
                    // onLoginFailed();
                    progressDialog.dismiss();
                }
            }, 3000);
}


@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == REQUEST_SIGNUP) {
        if (resultCode == RESULT_OK) {

            // TODO: Implement successful signup logic here
            // By default we just finish the Activity and log them in automatically
            this.finish();
        }
    }
}

@Override
public void onBackPressed() {
    // Disable going back to the MainActivity
    moveTaskToBack(true);
}

public void onLoginSuccess() {
    _loginButton.setEnabled(true);
    finish();
}

public void onLoginFailed() {
    Toast.makeText(getBaseContext(), "Login failed", Toast.LENGTH_LONG).show();

    _loginButton.setEnabled(true);
}

public boolean validate() {
    boolean valid = true;

    String email = _emailText.getText().toString();
    String password = _passwordText.getText().toString();

    if (email.isEmpty() || !android.util.Patterns.EMAIL_ADDRESS.matcher(email).matches()) {
        _emailText.setError("enter a valid email address");
        valid = false;
    } else {
        _emailText.setError(null);
    }

    if (password.isEmpty() || password.length() < 4 || password.length() > 10) {
        _passwordText.setError("between 4 and 10 alphanumeric characters");
        valid = false;
    } else {
        _passwordText.setError(null);
    }

    return valid;
}

}

回答6:

Use this function for validating email id:

 private boolean validateEmaillId(String emailId){

    return Pattern.compile("^(([\\w-]+\\.)+[\\w-]+|([a-zA-Z]{1}|[\\w-]{2,}))@"
            + "((([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
            + "[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\."
            + "([0-1]?[0-9]{1,2}|25[0-5]|2[0-4][0-9])\\.([0-1]?"
            + "[0-9]{1,2}|25[0-5]|2[0-4][0-9])){1}|"
            + "([a-zA-Z]+[\\w-]+\\.)+[a-zA-Z]{2,4})$").matcher(emailId).matches();
}

回答7:

I had a query in email pattern for more than one Email ID validation and for only one Email ID.I solved it by using :

public static final String patter_emails="^(\\s*,?\\s*[0-9a-za-z]([-.\\w]*[0-9a-za-z])*@([0-9a-za-z][-\\w]*[0-9a-za-z]\\.)+[a-za-z]{2,9})+\\s*$";
public static final String patter_email="^(\\s*[0-9a-za-z]([-.\\w]*[0-9a-za-z])*@([0-9a-za-z][-\\w]*[0-9a-za-z]\\.)+[a-za-z]{2,9})+\\s*$";

These above is used for pattern in Java and Android both.

check this by using:

pattern test: rubular.com

回答8:

android.util.Patterns.EMAIL_ADDRESS.matcher(target).matches()

回答9:

private void isValidEmail(String email_id) {

        if (email_id == null){
            checkTextView.setVisibility(View.VISIBLE);
            checkTextView.setText(LocaleController.getString("EnterValidEmail", R.string.EnterValidEmail));
            return;
        }
        if (android.util.Patterns.EMAIL_ADDRESS.matcher(email_id).matches()) {
            checkTextView.setVisibility(View.GONE);
        } else {
            checkTextView.setVisibility(View.VISIBLE);
            checkTextView.setText(LocaleController.getString("EnterValidEmail", R.string.EnterValidEmail));
        }

Take a textView ex.checkTextView and validate when the email is valid then the textview is gone otherwise it show the message

回答10:

Try below code:

Just call below method like,

if(emailValidator(mail.getText().toString())){
Toast.makeText(getActivity(), "valid email address",
                    Toast.LENGTH_SHORT).show();

}else{
Toast.makeText(getActivity(), "invalid email address",
                    Toast.LENGTH_SHORT).show();

}

    public static boolean emailValidator(final String mailAddress) {

            Pattern pattern;
            Matcher matcher;

            final String EMAIL_PATTERN = "^[_A-Za-z0-9-\\+]+(\\.[_A-Za-z0-9-]+)*@" + "[A-Za-z0-9-]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";

            pattern = Pattern.compile(EMAIL_PATTERN);
            matcher = pattern.matcher(mailAddress);
            return matcher.matches();

        }

回答11:

Assign a String variable to store the value of this EditText:

emailInput = mail.getText().toString().trim();

Use setError in your EditText:

if(!isValidEmail(emailInput)){
   mail.setError("Invalid"); /*"Invalid Text" or something like getString(R.string.Invalid)*/
   mail.requestFocus();
}

Create a method to check the email:

private boolean isValidEmail(String emailInput) {
    String EMAIL_PATTERN = "^[_A-Za-z0-9-\\+]+(\\.[_A-Za-z0-9-]+)*@"
            + "[A-Za-z0-9-]+(\\.[A-Za-z0-9]+)*(\\.[A-Za-z]{2,})$";

    Pattern pattern = Pattern.compile(EMAIL_PATTERN);
    Matcher matcher = pattern.matcher(emailInput);
    return matcher.matches();
}