How do I calculate the log of a number using bc?

问题:

This is the first time I am using bc. I want to calculate the log (base 10) of a number. How do I this?

回答1:

Invoke bc with the -l option (to enable the math library) like so

$ echo 'l(100)/l(10)' | bc -l
2.00000000000000000000

Use the l function which is the natural log. Take the log of the number you are interested in then divide by the natural log of 10.

回答2:

the logarithm of x in respect to base b can be computed given any logarithm function to an arbitrary base k -- that's actually pretty cool!

log_b(x) = log_k(x) / log_k(b)

e.g.

log_b(x) = ln(x) / ln(b)

if b=10:

log_10(x) = ln(x) / ln(10)

and -l in bc enables the math library

so that's why this works:

# bc -l
l(100) / l(10)
2.00000000000000000000

回答3:

If you start bc with the -l switch, then there's a function l() that calculates the natural log of its argument.

回答4:

Poster specifically requested log 10.

I have bc 1.06.95 on Ubuntu 12.10. "l(x)" in this version of BC is not base 10. It is natural log (base e). This is confirmed here and BC has worked this way since some time:

http://linux.about.com/od/commands/l/blcmdl1_bc.htm

I suspect what you need to make log base 10 work is the BC extension:

http://x-bc.sourceforge.net/extensions_bc.html

Not sure correct way to install this, and got errors trying to post it here.

Dominic-Luc Webb

回答5:

bc does not directly gives the logarithm in other than except or in other ways, using bc, we can calculate only ln(x). So, to get any other base logarithm, it is wise to remember some identities. The basic one is -

log base 10 (x) = log base e (x) / log base e (10)

Here I am giving you some examples of different base logarithms -

totan@Home-Computer ~ $ bc -l
bc 1.06.95
Copyright 1991-1994, 1997, 1998, 2000, 2004, 2006 Free Software Foundation, Inc.
This is free software with ABSOLUTELY NO WARRANTY.
For details type `warranty'. 

l(8)/l(2)
3.00000000000000000002

l(1000)/l(10)
3.00000000000000000000

l(100000)/l(100)
2.50000000000000000000

l(100000)/l(10)
5.00000000000000000001

l(81)/l(3)
4.00000000000000000001

l(64)/l(4)
3.00000000000000000000

quit()
totan@Home-Computer ~ $ 

Hope this helps you.

回答6:

bc -l

l(____) 

(fill in the blank there with your number)

I found tutorials at:

http://unix-simple.blogspot.com/2006/10/unix-basic-calculator.html

and

http://unix-simple.blogspot.com/2006/10/taking-roots-with-unix-basic.html

回答7:

Python can come in handy for this as,

log3=$(python -c  'import math; print math.log(3)')

Hope that helps!