I need some help. It is possible to only show one commit id? Since git log -3 show the log from 1 - 3, I just want to show only 3. What possible command will match for it?
I use the command
git log -3 --pretty=format:"%h"
the result is
ffbef87
cf0e073
1c76c5d
I only want to display the 1c76c5d only.
You can use git show
referencing the third parent from your current commit (i.e. the second ancestor from HEAD
). Also, git show
accepts the same format string as git log
:
git show HEAD~2 --pretty=format:"%h" --no-patch
Update (2016-12-01)
An even better way would be to use the rev-parse
plumbing command with the --short
option to output the abbreviated (7 characters) commit ID:
git rev-parse --short HEAD~2
Or you could also specify the exact length of the commit ID:
git rev-parse --short=4 HEAD~2
There is a tool for that:
git log -3 --pretty=format:"%h" | tail -n 1
You can include n
characters of the hash (instead of the default) with the following flag:
--abbrev=n
Relevant pieces of the Unix Philosophy
1) Make each program do one thing well. To do a new job, build afresh rather than complicate old programs by adding new "features".
2) Expect the output of every program to become the input to another, as yet unknown, program. Don't clutter output with extraneous information. Avoid stringently columnar or binary input formats. Don't insist on interactive input.
...
[i.e.]
- Write programs that do one thing and do it well.
- Write programs to work together.
https://en.wikipedia.org/wiki/Unix_philosophy
Since at least git version 2.3.8, you can use the --skip
option:
git log -1 --skip 2 --pretty=format:"%h"
Not sure which earlier versions of git support --skip
.