convert curl call into java urlconnection call

问题:

I have curl command:

curl -i -u guest:guest -H "content-type:application/json"
-XPUT \ http://localhost:15672/api/traces/%2f/my-trace \
-d'{"format":"text","pattern":"#"}'

And I want to create HTTP Request in Java API which will do the same thing. This curl command can be found in this README. It is used to start recording log on RabbitMQ. Response is not important.

For now I created something like this (I've deleted less important lines i.e. with catching exception etc.), but unfortunately it doesn't work:

url = new URL("http://localhost:15672/api/traces/%2f/my-trace");
uc = url.openConnection();

uc.setRequestProperty("Content-Type", "application/json");
uc.setRequestProperty("format","json");
uc.setRequestProperty("pattern","#")
String userpass = "guest:guest";
String basicAuth = "Basic " + javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes());
uc.setRequestProperty ("Authorization", basicAuth);

ENTIRE CODE

回答1:

This is final solution:

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;
import java.net.Proxy;
import java.net.InetSocketAddress;
import java.io.OutputStreamWriter;

public class Curl {

  public static void main(String[] args) {

    try {

    String url = "http://127.0.0.1:15672/api/traces/%2f/trololo";

    URL obj = new URL(url);
    HttpURLConnection conn = (HttpURLConnection) obj.openConnection();

    conn.setRequestProperty("Content-Type", "application/json");
    conn.setDoOutput(true);

    conn.setRequestMethod("PUT");

    String userpass = "user" + ":" + "pass";
    String basicAuth = "Basic " + javax.xml.bind.DatatypeConverter.printBase64Binary(userpass.getBytes("UTF-8"));
    conn.setRequestProperty ("Authorization", basicAuth);

    String data =  "{\"format\":\"json\",\"pattern\":\"#\"}";
    OutputStreamWriter out = new OutputStreamWriter(conn.getOutputStream());
    out.write(data);
    out.close();

    new InputStreamReader(conn.getInputStream());   

    } catch (Exception e) {
    e.printStackTrace();
    }

  }

}

回答2:

two problems that i can see:

• you aren't setting the request method, in your curl example it is "PUT"
• the '-d' data should be the request body, not request parameters (i.e. you should be writing that string to the request OutputStream)

also, when you do userpass.getBytes() you are getting the bytes using the default platform character encoding. this may or may not be the encoding that you desire. better to use an explicit character encoding (presumably the one the server is expecting).