I am practicing selenium in python and I wanted to fetch all the links on a web page using selenium.
For example, I want all the links in 'a href" tag from this website : http://psychoticelites.com/
I've written a script and it is working. But, it's rather giving me the object address. I've tried using the 'id' tag to get the value, but, it doesn't work.
My current script :-
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
driver = webdriver.Firefox()
driver.get("http://psychoticelites.com/")
assert "Psychotic" in driver.title
continue_link = driver.find_element_by_tag_name('a')
elem = driver.find_elements_by_xpath("//*[@href]")
#x = str(continue_link)
#print continue_link
#print elem
z = elem
print z
Any kind of clue/hint would be appreciated.
Well, you have to simply loop through the list.
elems = driver.find_elements_by_xpath("//a[@href]")
for elem in elems:
print elem.get_attribute("href")
find_elements_by_*
returns a list of elements (Note the spelling of 'elements'). Loop through the list, take each element and fetch the required attribute value you want from it. (in this case href
)
You can import the HTML dom using html dom library in python. You can find it over here and install it using PIP:
https://pypi.python.org/pypi/htmldom/2.0
from htmldom import htmldom
dom = htmldom.HtmlDom("https://www.github.com/")
dom = dom.createDom()
The above code creates a HtmlDom object.The HtmlDom takes a default parameter, the url of the page. Once the dom object is created, you need to call "createDom" method of HtmlDom. This will parse the html data and constructs the parse tree which then can be used for searching and manipulating the html data. The only restriction the library imposes is that the data whether it is html or xml must have a root element.
You can query the elements using the "find" method of HtmlDom object:
p_links = dom.find("a")
for link in p_links:
print ("URL: " +link.attr("href"))
The above code will print all the links/urls present on the web page
You can try something like:
links = driver.find_elements_by_partial_link_text('')