I would like to know how to ignore exceptions and continue infinite stream (in my case stream of locations)?
I'm fetching current user position (using Android-ReactiveLocation) and then sending them to my API (using Retrofit).
In my case, when exception occurs during network call (e.g. timeout) onError
method is invoked and stream stops itself. How to avoid it?
Activity:
private RestService mRestService;
private Subscription mSubscription;
private LocationRequest mLocationRequest = LocationRequest.create()
.setPriority(LocationRequest.PRIORITY_HIGH_ACCURACY)
.setInterval(100);
...
private void start() {
mRestService = ...;
ReactiveLocationProvider reactiveLocationProvider = new ReactiveLocationProvider(this);
mSubscription = reactiveLocationProvider.getUpdatedLocation(mLocationRequest)
.buffer(50)
.flatMap(locations -> mRestService.postLocations(locations)) // can throw exception
.subscribeOn(Schedulers.newThread())
.observeOn(AndroidSchedulers.mainThread())
.subscribe();
}
RestService:
public interface RestService {
@POST("/.../")
Observable<Response> postLocations(@Body List<Location> locations);
}
mRestService.postLocations(locations)
emit one item, then complete.
If an error occur, then it emit the error, which complete the stream.
As you call this method in a flatMap
, the error continue to your "main" stream, and then your stream stops.
What you can do is to transform your error into another item (as described here : https://stackoverflow.com/a/28971140/476690 ), but not on your main stream (as I presume you already tried) but on the mRestService.postLocations(locations)
.
This way, this call will emit an error, that will be transformed to an item/another observable and then complete. (without calling onError
).
On a consumer view, mRestService.postLocations(locations)
will emit one item, then complete, like if everything succeed.
mSubscription = reactiveLocationProvider.getUpdatedLocation(mLocationRequest)
.buffer(50)
.flatMap(locations -> mRestService.postLocations(locations).onErrorReturn((e) -> Collections.emptyList()) // can throw exception
.subscribeOn(Schedulers.newThread())
.observeOn(AndroidSchedulers.mainThread())
.subscribe();
You may want to use one of the error handling operators.
onErrorResumeNext( )
— instructs an Observable to emit a sequence of items if it encounters an error
onErrorReturn( )
— instructs an Observable to emit a particular item when it encounters an error
onExceptionResumeNext( )
— instructs an Observable to continue emitting items after it encounters an exception (but not another variety of throwable)
retry( )
— if a source Observable emits an error, resubscribe to it in the hopes that it will complete without error
retryWhen( )
— if a source Observable emits an error, pass that error to another Observable to determine whether to resubscribe to the source
Especialy retry
and onExceptionResumeNext
look promising in your case.
Just pasting the link info from @MikeN's answer incase it gets lost:
import rx.Observable.Operator;
import rx.functions.Action1;
public final class OperatorSuppressError<T> implements Operator<T, T> {
final Action1<Throwable> onError;
public OperatorSuppressError(Action1<Throwable> onError) {
this.onError = onError;
}
@Override
public Subscriber<? super T> call(final Subscriber<? super T> t1) {
return new Subscriber<T>(t1) {
@Override
public void onNext(T t) {
t1.onNext(t);
}
@Override
public void onError(Throwable e) {
onError.call(e);
}
@Override
public void onCompleted() {
t1.onCompleted();
}
};
}
}
and use it close to the observable source because other operators may
eagerly unsubscribe before that.
Observerable.create(connectToUnboundedStream()).lift(new OperatorSuppressError(log()).doOnNext(someStuff()).subscribe();
Note, however, that this suppresses the error delivery from the
source. If any onNext in the chain after it throws an exception, it is
still likely the source will be unsubscribed.
If you just want to ignore the error inside the flatMap
without returning an element do this:
flatMap(item ->
restService.getSomething(item).onErrorResumeNext(Observable.empty())
);
Try calling the rest service in a Observable.defer call. That way for every call you'll get a chance to use its own 'onErrorResumeNext' and the errors won't cause your main stream to complete.
reactiveLocationProvider.getUpdatedLocation(mLocationRequest)
.buffer(50)
.flatMap(locations ->
Observable.defer(() -> mRestService.postLocations(locations))
.onErrorResumeNext(<SOME_DEFAULT_TO_REACT_TO>)
)
........
That solution is originally from this thread -> RxJava Observable and Subscriber for skipping exception?, but I think it will work in your case too.
Add my solution for this problem:
privider
.compose(ignoreErrorsTransformer)
.subscribe()
private final Observable.Transformer<ResultType, ResultType> ignoreErrorsTransformer =
new Observable.Transformer<ResultType, ResultType>() {
@Override
public Observable<ResultType> call(Observable<ResultType> resultTypeObservable) {
return resultTypeObservable
.materialize()
.filter(new Func1<Notification<ResultType>, Boolean>() {
@Override
public Boolean call(Notification<ResultType> resultTypeNotification) {
return !resultTypeNotification.isOnError();
}
})
.dematerialize();
}
};
A slight modification of the solution (@MikeN) to enable finite streams to complete:
import rx.Observable.Operator;
import rx.functions.Action1;
public final class OperatorSuppressError<T> implements Operator<T, T> {
final Action1<Throwable> onError;
public OperatorSuppressError(Action1<Throwable> onError) {
this.onError = onError;
}
@Override
public Subscriber<? super T> call(final Subscriber<? super T> t1) {
return new Subscriber<T>(t1) {
@Override
public void onNext(T t) {
t1.onNext(t);
}
@Override
public void onError(Throwable e) {
onError.call(e);
//this will allow finite streams to complete
t1.onCompleted();
}
@Override
public void onCompleted() {
t1.onCompleted();
}
};
}
}