I'm trying to do something very simple and yet, after an hour of so of searching a I can't find a suitable answer so I must be missing something fairly obvious.
I'm trying to dynamically create filenames for use with ifstream. Whilst I understand various methods are available of doing this, I have settled on creating a std::string, and the using stringname.c_str to convert to const.
The problem is however that I need to create the string with a mix of variables and predefined text values. I'm getting compiler errors, so this must be a syntax issue.
Pseudo
std::string var = "sometext" + somevar + "sometext" + somevar;
Thanks!
Have you considered using stringstreams?
#include <string>
#include <sstream>
std::ostringstream oss;
oss << "sometext" << somevar << "sometext" << somevar;
std::string var = oss.str();
std::string var = "sometext" + somevar + "sometext" + somevar;
This doesn't work because the additions are performed left-to-right and "sometext"
(the first one) is just a const char *
. It has no operator+
to call. The simplest fix is this:
std::string var = std::string("sometext") + somevar + "sometext" + somevar;
Now, the first parameter in the left-to-right list of +
operations is a std::string
, which has an operator+(const char *)
. That operator produces a string, which makes the rest of the chain work.
You can also make all the operations be on var
, which is a std::string
and so has all the necessary operators:
var = "sometext";
var += somevar;
var += "sometext";
var += somevar;
In C++11 you can use std::to_string:
std::string var = "sometext" + std::to_string(somevar) + "sometext" + std::to_string(somevar);
See also boost::format:
#include <boost/format.hpp>
std::string var = (boost::format("somtext %s sometext %s") % somevar % somevar).str();
You can also use sprintf:
char str[1024];
sprintf(str, "somtext %s sometext %s", somevar, somevar);