Avoiding duplicated messages on JMS/ActiveMQ

问题:

There's a way to suppress duplicated messages on a queue defined on ActiveMQ server?

I tried to define manually JMSMessageID, (message.setJMSMessageID("uniqueid")), but server ignores this modification and deliver a message with built-in generated JMSMessageID.

By specification, I didn't found a reference about how to deduplicate messages.

In HornetQ, to deal with this problem, we need to declare the HQ specific property org.hornetq.core.message.impl.HDR_DUPLICATE_DETECTION_ID on message definition.

i.e.:

Message jmsMessage = session.createMessage();
String myUniqueID = "This is my unique id"; // Could use a UUID for this
message.setStringProperty(HDR_DUPLICATE_DETECTION_ID.toString(), myUniqueID);

Somebody knows if there's a similar solution for ActiveMQ?

回答1:

You should look at Apache Camel, it provides an Idempotent consumer component that would work with any JMS provider, see: http://camel.apache.org/idempotent-consumer.html

Using that in combination with the ActiveMQ component makes using JMS quite simple, see: http://camel.apache.org/activemq.html

回答2:

I doubt if ActiveMQ supports it natively, but it should be easy to implement an idempotent consumer. A way to do this would be to add a unique identifier to each message at the producer end, now at the consumer end using a store(db, cache etc), a check can be made to see if the message has been received before and continue to process based on that check.

I see a previous stackoverflow question along the same lines - Apache ActiveMQ 5.3 - How to configure a queue to reject duplicate messages? , that may also help.

回答3:

There is now support for removing duplicate messages baked into ActiveMQ transports. See the configuration values auditDepth and auditMaximumProducerNumber in the Connection Configuration Guide.

回答4:

There is a way to make ActiveMQ to filter duplicates based on a JMS property. it involves writing an Activemq Plugin. A basic broker filter that sends duplicate messages to the deadletter queue would be like this

import java.util.List;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

import org.apache.activemq.broker.Broker;
import org.apache.activemq.command.Message;
import org.apache.activemq.command.ActiveMQMessage;
import org.apache.activemq.broker.BrokerFilter;
import org.apache.activemq.broker.ConnectionContext;
import org.apache.activemq.command.ConnectionInfo;
import org.apache.activemq.broker.ProducerBrokerExchange;

public class DuplicateFilterBroker extends BrokerFilter {
    String messagePropertyName;
    boolean switchValue;

    public DuplicateFilterBroker(Broker next, String messagePropertyName) {
        super(next);
        this.messagePropertyName = messagePropertyName;
    }

    public boolean hasDuplicate(String propertyValue){
        switchValue = propertyValue;
        return switchValue;
    }

    public void send(ProducerBrokerExchange producerExchange, Message msg) throws Exception { 
        ActiveMQMessage amqmsg = (ActiveMQMessage)msg; 
        Object msgObj = msg.getMessage(); 
        if (msgObj instanceof javax.jms.Message) { 
            javax.jms.Message jmsMsg = (javax.jms.Message) msgObj; 
            if (!hasDuplicate(jmsMsg.getStringProperty(messagePropertyName))) {
                super.send(producerExchange, msg);
            }
            else {
               sendToDeadLetterQueue(producerExchange.getConnectionContext(), msg);
            } 
        }
    }  
}

回答5:

Seem the way that is suggested in the question, works for ActiveMQ too (2016/12). See the activemq-artemis guide. This requires the producer to set a specific property into the message.

Message jmsMessage = session.createMessage();
String myUniqueID = "This is my unique id";   // Could use a UUID for this
message.setStringProperty(HDR_DUPLICATE_DETECTION_ID.toString(), myUniqueID);

However the class containing the property is different: org.apache.activemq.artemis.core.message.impl.HDR_DUPLICATE_DETECTION_ID and the property value is _AMQ_DUPL_ID.