How to create an array of 20 random bytes?

问题:

How can I create an array of 20 random bytes in Java?

回答1:

Try the Random.nextBytes method:

byte[] b = new byte[20];
new Random().nextBytes(b);

回答2:

If you want a cryptographically strong random number generator (also thread safe) without using a third party API, you can use SecureRandom.

Java 6 & 7:

SecureRandom random = new SecureRandom();
byte[] bytes = new byte[20];
random.nextBytes(bytes);

Java 8 (even more secure):

byte[] bytes = new byte[20];
SecureRandom.getInstanceStrong().nextBytes(bytes);

回答3:

If you are already using Apache Commons Lang, the RandomUtils makes this a one-liner:

byte[] randomBytes = RandomUtils.nextBytes(20);

回答4:

Java 7 introduced ThreadLocalRandom which is isolated to the current thread.

This is an another rendition of maerics's solution.

final byte[] bytes = new byte[20];
ThreadLocalRandom.current().nextBytes(bytes);

回答5:

Create a Random object with a seed and get the array random by doing:

public static final int ARRAY_LENGTH = 20;

byte[] byteArray = new byte[ARRAY_LENGTH];
new Random(System.currentTimeMillis()).nextBytes(byteArray);
// get fisrt element
System.out.println("Random byte: " + byteArray[0]);