getting the youtube id from a link

2019-02-01 14:25发布

问题:

I got this code to get the youtube id from the links like www.youtube.com/watch?v=xxxxxxx

  URL youtubeURL = new URL(link);
  youtubeURL.getQuery();

basically this will get me the id easily v=xxxxxxxx

but I noticed sometime youtube links will be like this

http://gdata.youtube.com/feeds/api/videos/xxxxxx

I am getting the links from a feed so do I need to build a regex for that or theres a parser to get that for me ?

回答1:

Tried the other ones but failed in my case - adjusted the regex to fit for my urls

String pattern = "(?<=watch\\?v=|/videos/|embed\\/)[^#\\&\\?]*";

    Pattern compiledPattern = Pattern.compile(pattern);
    Matcher matcher = compiledPattern.matcher(url);

    if(matcher.find()){
        return matcher.group();
    }

This one works for: (you could also implement a security check youtubeid length = 11 )

http://www.youtube.com/embed/Woq5iX9XQhA?html5=1

http://www.youtube.com/watch?v=384IUU43bfQ

http://gdata.youtube.com/feeds/api/videos/xTmi7zzUa-M&whatever

Woq5iX9XQhA

384IUU43bfQ

xTmi7zzUa-M



回答2:

This regex would do the trick:

(?<=videos\/|v=)([\w-]+)

This means that we're first looking for video/ or v= then captures all the following characters that can be in word (letters, digits, and underscores) and hyphens.

Example in java:

public static void main(String[] args) {

    String link = "http://gdata.youtube.com/feeds/api/videos/xTmi7zzUa-M&whatever";
    String pattern = "(?:videos\\/|v=)([\\w-]+)";

    Pattern compiledPattern = Pattern.compile(pattern);
    Matcher matcher = compiledPattern.matcher(link);

    if(matcher.find()){
        System.out.println(matcher.group());
    }
}

Output:

xTmi7zzUa-M


回答3:

public static String getYoutubeVideoId(String youtubeUrl)
 {
 String video_id="";
  if (youtubeUrl != null && youtubeUrl.trim().length() > 0 && youtubeUrl.startsWith("http"))
 {

String expression = "^.*((youtu.be"+ "\\/)" + "|(v\\/)|(\\/u\\/w\\/)|(embed\\/)|(watch\\?))\\??v?=?([^#\\&\\?]*).*"; // var regExp = /^.*((youtu.be\/)|(v\/)|(\/u\/\w\/)|(embed\/)|(watch\?))\??v?=?([^#\&\?]*).*/;
 CharSequence input = youtubeUrl;
 Pattern pattern = Pattern.compile(expression,Pattern.CASE_INSENSITIVE);
 Matcher matcher = pattern.matcher(input);
 if (matcher.matches())
 {
String groupIndex1 = matcher.group(7);
 if(groupIndex1!=null && groupIndex1.length()==11)
 video_id = groupIndex1;
 }
 }
 return video_id;
 }


回答4:

That pattern worked for me:

"http(?:s?)://(?:www\.)?youtu(?:be\.com/watch\?v=|\.be/)([\w\-]+)(&(amp;)?[\w\?=‌​]*)?"

source: Regular expression for youtube links



回答5:

Got a better solution from this link.

Use the following method to get the videoId from the link.

YoutubeHelper.java

import com.google.inject.Singleton; 

import java.util.regex.Matcher;
import java.util.regex.Pattern;

@Singleton 
public class YouTubeHelper { 

    final String youTubeUrlRegEx = "^(https?)?(://)?(www.)?(m.)?((youtube.com)|(youtu.be))/";
    final String[] videoIdRegex = { "\\?vi?=([^&]*)","watch\\?.*v=([^&]*)", "(?:embed|vi?)/([^/?]*)", "^([A-Za-z0-9\\-]*)"};

    public String extractVideoIdFromUrl(String url) {
        String youTubeLinkWithoutProtocolAndDomain = youTubeLinkWithoutProtocolAndDomain(url);

        for(String regex : videoIdRegex) {
            Pattern compiledPattern = Pattern.compile(regex);
            Matcher matcher = compiledPattern.matcher(youTubeLinkWithoutProtocolAndDomain);

            if(matcher.find()){
                return matcher.group(1);
            } 
        } 

        return null; 
    } 

    private String youTubeLinkWithoutProtocolAndDomain(String url) {
        Pattern compiledPattern = Pattern.compile(youTubeUrlRegEx);
        Matcher matcher = compiledPattern.matcher(url);

        if(matcher.find()){
            return url.replace(matcher.group(), "");
        } 
        return url;
    } 
} 

Hope this helps.



回答6:

Without knowing the complete specification for all the possible YouTube URLs, this seems to work for the examples you provided:

//*EDIT* - fixed to hopefully support more recent youtube link styles/formats:
(?<=watch\?v=|/videos/|/embed/|youtu.be/)[^&#?]*

... matches PjDw3azfZWI from either of these URLS:

http://www.youtube.com/watch?v=PjDw3azfZWI#t=31m08s
http://gdata.youtube.com/feeds/api/videos/PjDw3azfZWI

You would need a little more to get that particular info if you did not know that these were from youtube, though that's a pretty quick check

Keep in mind that if you are trying to use only the result of the getQuery() method, it will not be possible to extract the result from the http://gdata.youtube.com/feeds/api/videos/PjDw3azfZWI URL, as this URL does not have a query part to it...

Java Example:

Pattern rex = Pattern.compile("(?<=watch\\?v=|/videos/)[^&#]*");
Matcher m = rex.matcher(link);
String YouTubeVideoID = m.group();


回答7:

This was worked for me

public static String getYoutubeVideoId(String youtubeUrl) {
    String videoId = "";
    if (youtubeUrl != null && youtubeUrl.trim().length() > 0 && youtubeUrl.startsWith("http")) {

        String expression = "^.*((youtu.be"+ "/)" + "|(v/)|(/u/w/)|(embed/)|(watch\\?))\\??v?=?([^#&\\?]*).*"; // var regExp = /^.*((youtu.be\/)|(v\/)|(\/u\/\w\/)|(embed\/)|(watch\?))\??v?=?([^#\&\?]*).*/;
        Pattern pattern = Pattern.compile(expression,Pattern.CASE_INSENSITIVE);
        Matcher matcher = pattern.matcher(youtubeUrl);
        if (matcher.matches()) {
            String groupIndex1 = matcher.group(7);
            if(groupIndex1!=null && groupIndex1.length()==11)
                videoId = groupIndex1;
        }

    }
    return videoId;
}

Source link



回答8:

This doesn't use a regex but should still do the job.

/**
 * Returns the video id of a YouTube watch link.
 */
public static String getVideoId(String watchLink)
{
    return watchLink.substring(watchLink.length() - 11);
}


回答9:

This will work me and simple

public static String getVideoId(@NonNull String videoUrl) {
    String reg = "(?:youtube(?:-nocookie)?\\.com\\/(?:[^\\/\\n\\s]+\\/\\S+\\/|(?:v|e(?:mbed)?)\\/|\\S*?[?&]v=)|youtu\\.be\\/)([a-zA-Z0-9_-]{11})";
    Pattern pattern = Pattern.compile(reg, Pattern.CASE_INSENSITIVE);
    Matcher matcher = pattern.matcher(videoUrl);

    if (matcher.find())
        return matcher.group(1);
    return null;
}