I'm trying to put a css3 gradient over the top of a background image. Using the code below puts a background image on top of my gradient, but i'm trying to do it the other way around, so the gradient acts as a mask on top.
url(images/darkwood.png),
-webkit-gradient(linear, 0 0, 0 100%, from(#EEF), to(#000)) 300px 50px no-repeat,
-webkit-gradient(linear, 0 0, 0 100%, from(#EFE), to(#000)) 0 0 no-repeat;
background:
url(images/darkwood.png),
-moz-linear-gradient(#EEF, rgba(0,0,0,1)) 300px 50px no-repeat,
-moz-linear-gradient(#EFE, rgba(0,0,0,1)) 0 0 no-repeat;
Thanks for your help
I have do this for one of my website, Hope it's work for you;
body {
margin: 0;
padding: 0;
background: url('https://i.stack.imgur.com/MUsp6.jpg') repeat;
}
body:before {
content: " ";
width: 100%;
height: 100%;
position: absolute;
z-index: -1;
top: 0;
left: 0;
background: -webkit-radial-gradient(top center, ellipse cover, rgba(255,255,255,0.2) 0%,rgba(0,0,0,0.5) 100%);
}
The example from this answer won't work with resizeable divs.
Your code would work fine. But as I understand it, CSS reads from the right to the left.
So you would have to use the following:
div {
background: -webkit-radial-gradient(top center, ellipse cover, rgba(255,255,255,0.2) 0%,rgba(0,0,0,0.5) 100%), url('http://www.google.co.uk/logos/classicplus.png') repeat;
}
Example:
http://sapphion.com/2011/11/css3-background-gradient-on-top-of-an-image/