Finally I'm able to use std::vector in python using the [] operator. The trick is to simple provide a container in the boost C++ wrapper which handles the internal vector stuff:
#include <boost/python.hpp>
#include <vector>
class world
{
std::vector<double> myvec;
void add(double n)
{
this->myvec.push_back(n);
}
std::vector<double> show()
{
return this->myvec;
}
};
BOOST_PYTHON_MODULE(hello)
{
class_<std::vector<double> >("double_vector")
.def(vector_indexing_suite<std::vector<double> >())
;
class_<World>("World")
.def("show", &World::show)
.def("add", &World::add)
;
}
The other challenge is: Howto translate python lists into std::vectors? I tried to add a c++ class expecting a std::vector as parameter and added the corresponding wrapper code:
#include <boost/python.hpp>
#include <vector>
class world
{
std::vector<double> myvec;
void add(double n)
{
this->myvec.push_back(n);
}
void massadd(std::vector<double> ns)
{
// Append ns to this->myvec
}
std::vector<double> show()
{
return this->myvec;
}
};
BOOST_PYTHON_MODULE(hello)
{
class_<std::vector<double> >("double_vector")
.def(vector_indexing_suite<std::vector<double> >())
;
class_<World>("World")
.def("show", &World::show)
.def("add", &World::add)
.def("massadd", &World::massadd)
;
}
But if doing so, I end up with the following Boost.Python.ArgumentError:
>>> w.massadd([2.0,3.0])
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
Boost.Python.ArgumentError: Python argument types in
World.massadd(World, list)
did not match C++ signature:
massadd(World {lvalue}, std::vector<double, std::allocator<double> >)
Can anybody tell me how I can access python lists within my c++ function?
Thanks,
Daniel
To make your C++ method accept Python lists you should use boost::python::list
void massadd(boost::python::list& ns)
{
for (int i = 0; i < len(ns); ++i)
{
add(boost::python::extract<double>(ns[i]));
}
}
Here's what I use:
#include <boost/python/stl_iterator.hpp>
namespace py = boost::python;
template< typename T >
inline
std::vector< T > to_std_vector( const py::object& iterable )
{
return std::vector< T >( py::stl_input_iterator< T >( iterable ),
py::stl_input_iterator< T >( ) );
}
Should you find the input type (py::object) too liberal, feel free to specify stricter types (py::list in your case).
Based on the above answers I created an example of accessing python lists in C++ as well as returning a python list from a C++ function:
#include <boost/python.hpp>
#include <string>
namespace py = boost::python;
// dummy class
class drow{
public:
std::string word;
drow(py::list words);
py::list get_chars();
};
// example of passing python list as argument (to constructor)
drow::drow(py::list l){
std::string w;
std::string token;
for (int i = 0; i < len(l) ; i++){
token = py::extract<std::string>(l[i]);
w += token;
}
this -> word = w;
}
// example of returning a python list
py::list drow::get_chars(){
py::list char_vec;
for (auto c : word){
char_vec.append(c);
}
return char_vec;
}
// binding with python
BOOST_PYTHON_MODULE(drow){
py::class_<drow>("drow", py::init<py::list>())
.def("get_chars", &drow::get_chars);
}
For a build example and a test python script take a look here
Thank you Arlaharen & rdesgroppes for the pointers (pun not intended).
To get automatic conversion from python lists, you have to define a converter, which
- checks if the list is convertible to your type (i.e. that it is a sequence; additionally, you can also check whether all elements are of required type, but that can be handled in the second step as well)
- returns the new object, if the first step succeeded; throw exception if a sequence element is not convertible to what you need.
I can't find now anything else than my code, you can copy&paste this template (it is specialized at the end of that file for various contained types).