How to find the path a Ruby Gem is installed at (i

问题:

Gem.bin_path('cucumber', 'cucumber')

Will return the binary/executable's path. It seems there is no such function to return the library path. Which in this case would, ideally, return:

/home/hedge/.rvm/gems/ruby-1.9.2-p136@bbb-bdd-meta-bdd/gems/cucumber-0.10.0/lib

Have I missed something or is there a simple/one method way to get this information?

Updated: No CLI or non-stdlib suggestions please.

回答1:

The problem with the checked answer is that you must "require" the rubygem or it won't work. Often this is undesireable because if you're working with an executable gem, you don't want to "require" it or you'll get a bunch of warnings.

This is a universal solution for executables and libs:

spec = Gem::Specification.find_by_name("cucumber")
gem_root = spec.gem_dir
gem_lib = gem_root + "/lib"

If you want to get really technical, there isn't just one lib directory. The gemspec has a "require_paths" array of all the directorys to search (added to $LOAD_PATH). So, if you want an array of the require_paths, use this:

gem_lib = gem_root + "/" + spec.require_paths[0]

No need for bundler.

回答2:

After the gem has been loaded with require, you find the lib path using Gem.loaded_specs as follows:

require 'rubygems'
require 'cucumber'
gem_root = Gem.loaded_specs['cucumber'].full_gem_path
gem_lib = File.join(gem_root, 'lib')

回答3:

I'm not sure why you're doing this, but if you're on the command line, use gem env.

回答4:

Try using bundle show cucumber.

Which, from looking at the source of bundler does something like:

spec = Bundler.load.specs.find{|s| s.name == name }
spec.full_gem_path

You are using bundler, right?