Is there a method to generate a standard 128bit GU

问题:

Is there a built in function equivalent to .NET's

Guid.NewGuid();

in Cocoa?

My desire is to produce a string along the lines of 550e8400-e29b-41d4-a716-446655440000 which represents a unique identifier.

回答1:

UUIDs are handled in Core Foundation, by the CFUUID library. The function you are looking for is CFUUIDCreate.

FYI for further searches: these are most commonly known as UUIDs, the term GUID isn't used very often outside of the Microsoft world. You might have more luck with that search term.

回答2:

Some code:

For a string UUID, the following class method should do the trick:

+(NSString*)UUIDString {
    CFUUIDRef theUUID = CFUUIDCreate(NULL);
    CFStringRef string = CFUUIDCreateString(NULL, theUUID);
    CFRelease(theUUID);
    return [(NSString *)string autorelease];
}

if you really want the bytes (not the string):

+(CFUUIDBytes)UUIDBytes {
    CFUUIDRef theUUID = CFUUIDCreate(NULL);
    CFUUIDBytes bytes = CFUUIDGetUUIDBytes(theUUID);
    CFRelease(theUUID);
    return bytes;
}

where CFUUIDBytes is a struct of the UUID bytes.

回答3:

At least on MacOSX 10.5.x you might use the command line tool "uuidgen" to get your string e.g.

$ uuidgen

054209C4-3873-4679-8104-3C18AE780512

there's also an option -hdr with this comand that conveniently generates it in header style

See man-page for further infos.

回答4:

or there's the uuidgen command line tool.

回答5:

Since 10.8 you could also use: NSString *uuidString = [[NSUUID UUID] UUIDString];

回答6:

Check out the Wikipedia article and the Core Foundation page.

回答7:

Since 10.3 or so, you can use [[NSProcessInfo processInfo] globallyUniqueString]. However, while this currently generates a UUID, it never has been and still isn't guaranteed to do that, so if you really need a UUID and not just any unique string, you should use CFUUID.