Drop multiple tables in one shot in mysql

问题:

How to drop multiple tables from one single database at one command. something like,

> use test; 
> drop table a,b,c;

where a,b,c are the tables from database test.

回答1:

Example:

Let's say table A has two children B and C. Then we can use the following syntax to drop all tables.

DROP TABLE IF EXISTS B,C,A;

This can be placed in the beginning of the script instead of individually dropping each table.

回答2:

SET foreign_key_checks = 0;
DROP TABLE IF EXISTS a,b,c;
SET foreign_key_checks = 1;

Then you do not have to worry about dropping them in the correct order, nor whether they actually exist.

N.B. this is for MySQL only (as in the question). Other databases likely have different methods for doing this.

回答3:

declare @sql1 nvarchar(max) 
SELECT @sql1 =
  STUFF(
         (
           select ' drop table dbo.[' + name + ']'

           FROM sys.sysobjects AS sobjects
           WHERE (xtype = 'U') AND (name LIKE 'GROUP_BASE_NEW_WORK_%')
           for xml path('')
        ),
     1, 1, '')

  execute sp_executesql @sql1