Developing same UI for 3.5, 4.0 (updated 4.7 and 5

问题:

1. I have developed app considering 3.5 inch with .xib files and not storyboard.
2. I am unable to find any tutorial or guide which will help me in designing app similar for all screens.
3. I am using Xcode 5.0.1
4. I am developing only plain app with no auto layout and only for iOS 6 and iOS 7 (IPhone).

5. Below is the screenshot how it differs on different screens.

   A. IPhone iOS 6 simulator:

   B. 3.5 Inch (Ios 6 and Ios 7) C. 4.0 Inch (Ios 6 and Ios 7)

Update: Please update below answers to also know 4.7 and 5.5 inches screen.

回答1:

If you want check it Programmatically :

For checking Retina (3.5/4 inch Screen) or Non-Retina

if ([[UIScreen mainScreen] respondsToSelector:@selector(scale)]) {
    if ([[UIScreen mainScreen] scale] == 2.0) {
       if([UIScreen mainScreen].bounds.size.height == 568){
          // iPhone retina-4 inch
        } else{
         // iPhone retina-3.5 inch
        }
}
else {
    // not retina display
}

Update:

checking ios8 or ios 7

NSOperatingSystemVersion ios8_0_0 = (NSOperatingSystemVersion){8, 0, 0};
 if ([[NSProcessInfo processInfo] isOperatingSystemAtLeastVersion:ios8_0_0]) {
    // iOS 8 stuff
 } else {
    // iOS 7 and below stuff
 }

For checking All retina iPhone Programmatically:

if ([[UIScreen mainScreen] respondsToSelector:@selector(scale)]) {
      if ([[UIScreen mainScreen] scale] == 2.0) {

           if([UIScreen mainScreen].bounds.size.height == 667){
             // iPhone retina-4.7 inch(iPhone 6)
           } 
           else if([UIScreen mainScreen].bounds.size.height == 568){
             // iPhone retina-4 inch(iPhone 5 or 5s)
           } 
           else{
            // iPhone retina-3.5 inch(iPhone 4s)
          }
      }
      else if ([[UIScreen mainScreen] scale] == 3.0)
      {
           //if you want to detect the iPhone 6+ only 
           if([UIScreen mainScreen].bounds.size.height == 736.0){
              //iPhone retina-5.5 inch screen(iPhone 6 plus)
           }
           //iPhone retina-5.5 inch screen(iPhone 6 plus)
      }
 }

Also check this

#define IS_IPHONE_5 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 568.0)
#define IS_IPHONE_6 (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 667.0)
#define IS_IPHONE_6_PLUS (IS_IPHONE && [[UIScreen mainScreen] bounds].size.height == 736.0)

FOR Swift 3.0

if UIDevice().userInterfaceIdiom == .Phone {
    switch UIScreen.mainScreen().nativeBounds.height {
    case 480:
        print("iPhone Classic")
    case 960:
        print("iPhone 4 or 4S")
    case 1136:
        print("iPhone 5 or 5S or 5C")
    case 1334:
        print("iPhone 6 or 6S or 7")
    case 1920:
        print("iPhone 6+ or 6S+ or 7+")
    default:
        print("unknown")
    }
}

You can also extend UIDevice as follow:

extension UIDevice {
    var iPhone: Bool {
        return UIDevice().userInterfaceIdiom == .Phone
    }
    enum ScreenType: String {
        case iPhone4
        case iPhone5
        case iPhone6/iPhone7
        case iPhone6Plus/iPhone6splus/iPhone7plus
        case unknown
    }
    var screenType: ScreenType {
        guard iPhone else { return .unknown }
        switch UIScreen.mainScreen().nativeBounds.height {
        case 960:
            return .iPhone4
        case 1136:
           return .iPhone5
        case 1334:
            return .iPhone6/iPhone7
        case 1920:
           return .iPhone6Plus/iPhone6splus/iPhone7plus
        default:
           return .unknown
        }
    }
}

---

edit/update Xcode 8.1 • Swift 3.0.1

extension UIDevice {
    var iPhone: Bool {
        return UIDevice().userInterfaceIdiom == .phone
    }
    enum ScreenType: String {
        case iPhone4
        case iPhone5
        case iPhone6/iPhone7 
        case iPhone6Plus/iPhone6splus/iPhone7plus
        case unknown
    }
    var screenType: ScreenType {
        guard iPhone else { return .unknown }
        switch UIScreen.main.nativeBounds.height {
        case 960:
            return .iPhone4
        case 1136:
            return .iPhone5
        case 1334:
            return .iPhone6/iPhone7
        case 1920:
            return .iPhone6Plus/iPhone6splus/iPhone7plus
        default:
            return .unknown
        }
    }
}

may it will help you .

Happy coding.

回答2:

Put below lines in prefix.pch

#define IS_DEVICE_RUNNING_IOS_7_AND_ABOVE() ([[[UIDevice currentDevice] systemVersion] compare:@"7.0" options:NSNumericSearch] != NSOrderedAscending)
#define iPhoneVersion ([[UIScreen mainScreen] bounds].size.height == 568 ? 5 : ([[UIScreen mainScreen] bounds].size.height == 480 ? 4 : ([[UIScreen mainScreen] bounds].size.height == 667 ? 6 : ([[UIScreen mainScreen] bounds].size.height == 736 ? 61 : 999))))

Now in programming you can say...

if (IS_DEVICE_RUNNING_IOS_7_AND_ABOVE()) {
    NSLog("This is iOS 7");
} else {
    NSLog("This is iOS 6 or below");
}


if (iPhoneVersion==4) {
    NSLog("This is 3.5 inch iPhone - iPhone 4s or below");
} else if (iPhoneVersion==5) {
    NSLog("This is 4 inch iPhone - iPhone 5 family");
} else if (iPhoneVersion==6) {
    NSLog("This is 4.7 inch iPhone - iPhone 6");
} else if (iPhoneVersion==61) {
    NSLog("This is 5.5 inch iPhone - iPhone 6 Plus.. The BIGGER");
} else {
    NSLog("This is iPad");
}

回答3:

You can use auto layout or code. In code you can use layoutSubviews method. Just check view height to discover is it a iPhone 3.5 or 4 inch and do your set up:

-(void)layoutSubviews
{
    if (self.view.bounds.size.height == 568)
    {
        [self.textField setFrame:CGRectMake(0, 0, 100, 30)];
        //... other setting for iPhone 4inch
    }
    else
    {
        [self.textField setFrame:CGRectMake(0, 0, 100, 30)];
        //... other setting for iPhone 3.5 inch
    }
}

回答4:

SWIFT:

if(DeviceType.IS_IPHONE_4_OR_LESS)
{
//DO THIS 
}
//*********************************************************************
    enum UIUserInterfaceIdiom : Int
    {
        case Unspecified
        case Phone
        case Pad
    }

    struct ScreenSize
    {
        static let SCREEN_WIDTH         = UIScreen.mainScreen().bounds.size.width
        static let SCREEN_HEIGHT        = UIScreen.mainScreen().bounds.size.height
        static let SCREEN_MAX_LENGTH    = max(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
        static let SCREEN_MIN_LENGTH    = min(ScreenSize.SCREEN_WIDTH, ScreenSize.SCREEN_HEIGHT)
    }

    struct DeviceType
    {
        static let IS_IPHONE_4_OR_LESS  = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH < 568.0
        static let IS_IPHONE_5          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 568.0
        static let IS_IPHONE_6          = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 667.0
        static let IS_IPHONE_6P         = UIDevice.currentDevice().userInterfaceIdiom == .Phone && ScreenSize.SCREEN_MAX_LENGTH == 736.0
        static let IS_IPAD              = UIDevice.currentDevice().userInterfaceIdiom == .Pad && ScreenSize.SCREEN_MAX_LENGTH == 1024.0
    }

回答5:

you can also define globally.

#define isIPHONE5 ([UIScreen mainScreen].bounds.size.height == 568.f)
if(isIPHONE5){

// iphone 5 screen

}else{

// iphone 3.5 screen

}