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问题:
I was wondering if there is some way to specify a custom aggregation function for spark dataframes over multiple columns.
I have a table like this of the type (name, item, price):
john | tomato | 1.99
john | carrot | 0.45
bill | apple | 0.99
john | banana | 1.29
bill | taco | 2.59
to:
I would like to aggregate the item and it's cost for each person into a list like this:
john | (tomato, 1.99), (carrot, 0.45), (banana, 1.29)
bill | (apple, 0.99), (taco, 2.59)
Is this possible in dataframes? I recently learned about collect_list
but it appears to only work for one column.
回答1:
The easiest way to do this as a DataFrame
is to first collect two lists, and then use a UDF
to zip
the two lists together. Something like:
import org.apache.spark.sql.functions.{collect_list, udf}
import sqlContext.implicits._
val zipper = udf[Seq[(String, Double)], Seq[String], Seq[Double]](_.zip(_))
val df = Seq(
("john", "tomato", 1.99),
("john", "carrot", 0.45),
("bill", "apple", 0.99),
("john", "banana", 1.29),
("bill", "taco", 2.59)
).toDF("name", "food", "price")
val df2 = df.groupBy("name").agg(
collect_list(col("food")) as "food",
collect_list(col("price")) as "price"
).withColumn("food", zipper(col("food"), col("price"))).drop("price")
df2.show(false)
# +----+---------------------------------------------+
# |name|food |
# +----+---------------------------------------------+
# |john|[[tomato,1.99], [carrot,0.45], [banana,1.29]]|
# |bill|[[apple,0.99], [taco,2.59]] |
# +----+---------------------------------------------+
回答2:
Consider using the struct
function to group the columns together before collecting as a list:
import org.apache.spark.sql.functions.{collect_list, struct}
import sqlContext.implicits._
val df = Seq(
("john", "tomato", 1.99),
("john", "carrot", 0.45),
("bill", "apple", 0.99),
("john", "banana", 1.29),
("bill", "taco", 2.59)
).toDF("name", "food", "price")
df.groupBy($"name")
.agg(collect_list(struct($"food", $"price")).as("foods"))
.show(false)
Outputs:
+----+---------------------------------------------+
|name|foods |
+----+---------------------------------------------+
|john|[[tomato,1.99], [carrot,0.45], [banana,1.29]]|
|bill|[[apple,0.99], [taco,2.59]] |
+----+---------------------------------------------+
回答3:
Maybe a better way than the zip
function (since UDF and UDAF are very bad to performance) is to wrap the two columns into Struct
.
This would probably work as well:
df.select('name, struct('food, 'price).as("tuple"))
.groupBy('name)
.agg(collect_list('tuple).as("tuples"))
回答4:
Here is an option by converting the data frame to a RDD of Map and then call a groupByKey
on it. The result would be a list of key-value pairs where value is a list of tuples.
df.show
+----+------+----+
| _1| _2| _3|
+----+------+----+
|john|tomato|1.99|
|john|carrot|0.45|
|bill| apple|0.99|
|john|banana|1.29|
|bill| taco|2.59|
+----+------+----+
val tuples = df.map(row => row(0) -> (row(1), row(2)))
tuples: org.apache.spark.rdd.RDD[(Any, (Any, Any))] = MapPartitionsRDD[102] at map at <console>:43
tuples.groupByKey().map{ case(x, y) => (x, y.toList) }.collect
res76: Array[(Any, List[(Any, Any)])] = Array((bill,List((apple,0.99), (taco,2.59))), (john,List((tomato,1.99), (carrot,0.45), (banana,1.29))))