i want to dynamically add a class to all rows of a table except the first and last row. how would i do this without assigning a css class to the rows to identify them. I am getting all but the first row currently with
$("#id").find("tr:gt(0)")
i need to combine this with not("tr:last")
somehow maybe?
Drop the gt()
, as I'd assume it's a tiny bit slower than :first
.
Use not()
in conjunction with :first
and :last
:
$('table#tbl > tbody > tr').not(':first').not(':last').addClass('highlight');
Most browsers automatically add an tbody
element in the table markup if that's missing, that is why the immediate children selector was failing – there were no <tr>
elements as an immediate children to the <table>
tag.
I am not 100% sure this is the way all browsers do it, so it would be safer to just add the <tbody>
manually. Otherwise you need a little sniffing and cannot do it as an one liner:
if($('table#tbl > tbody').size() > 0) {
$('table#tbl > tbody > tr').not(':first').not(':last').addClass('highlight');
} else {
$('table#tbl > tr').not(':first').not(':last').addClass('highlight');
}
Hope this solves your problem!
Try this:
.not(':first').not(':last')
why not just this?
$('table tr:not(:first-child):not(:last-child)');
works as pure CSS selector as well.
You can combine the .not()
methods into one by separating the selectors with commas:
$('#id tr').not(':first, :last');
$('#id tr:not(:first, :last');
Note that the second one is not valid in pure CSS, only as a jQuery selector. For pure CSS you'd have to use @Sumit's answer.
Strange the suggestions posted did not work, they should all work! BUT...
If it did not work, do it this way.... slightly slower but MUST WORK!!
TRY:
$('table#tbl tr').addClass('highlight');
$('table#tbl tr:first-child').removeClass('highlight');
$('table#tbl tr:last-child').removeClass('highlight');
You can also use the .slice()
method to remove the first/last elements from the set:
$('table tr').slice(1, -1);
The .slice()
method essentially creates a new jQuery object with a subset of the elements specified in the initial set. In this case, it will exclude the elements with an index of 1
and -1
, which are the first/last elements respectively.
Example:
$('table tr').slice(1, -1).css('background-color', '#f00');
table { width: 100%; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr><td>1</td></tr><tr><td>2</td></tr>
<tr><td>3</td></tr><tr><td>4</td></tr>
<tr><td>5</td></tr><tr><td>6</td></tr>
</table>
Of course, you can also negate :first-child
/:last-child
using :not()
:
$('table tr:not(:first-child):not(:last-child)').css('background-color', '#f00');
table { width: 100%; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr><td>1</td></tr><tr><td>2</td></tr>
<tr><td>3</td></tr><tr><td>4</td></tr>
<tr><td>5</td></tr><tr><td>6</td></tr>
</table>
You can also combine :nth-child(n+2)
and :nth-last-child(n+2)
:
$('table tr:nth-child(n+2):nth-last-child(n+2)').css('background-color', '#f00');
table { width: 100%; }
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table>
<tr><td>1</td></tr><tr><td>2</td></tr>
<tr><td>3</td></tr><tr><td>4</td></tr>
<tr><td>5</td></tr><tr><td>6</td></tr>
</table>