How to use patterns in the case statement in bash

2019-01-30 10:59发布

问题:

The man page says that case statements use "filename expansion pattern matching".
I usually want to have short names for some parameters, so I go:

case $1 in
    req|reqs|requirements) TASK="Functional Requirements";;
    met|meet|meetings) TASK="Meetings with the client";;
esac

logTimeSpentIn "$TASK"

I tried patterns like req* or me{e,}t which I understand would expand correctly to match those values in the context of filename expansion, but it doesn't work.

回答1:

Brace expansion doesn't work, but *, ? and [] do. If you set shopt -s extglob then you can also use extended pattern matching:

  • ?() - zero or one occurrences of pattern
  • *() - zero or more occurrences of pattern
  • +() - one or more occurrences of pattern
  • @() - one occurrence of pattern
  • !() - anything except the pattern

Here's an example:

shopt -s extglob
for arg in apple be cd meet o mississippi
do
    # call functions based on arguments
    case "$arg" in
        a*             ) foo;;    # matches anything starting with "a"
        b?             ) bar;;    # matches any two-character string starting with "b"
        c[de]          ) baz;;    # matches "cd" or "ce"
        me?(e)t        ) qux;;    # matches "met" or "meet"
        @(a|e|i|o|u)   ) fuzz;;   # matches one vowel
        m+(iss)?(ippi) ) fizz;;   # matches "miss" or "mississippi" or others
        *              ) bazinga;; # catchall, matches anything not matched above
    esac
done


回答2:

I don't think you can use braces.

According to the Bash manual about case in Conditional Constructs.

Each pattern undergoes tilde expansion, parameter expansion, command substitution, and arithmetic expansion.

Nothing about Brace Expansion unfortunately.

So you'd have to do something like this:

case $1 in
    req*)
        ...
        ;;
    met*|meet*)
        ...
        ;;
    *)
        # You should have a default one too.
esac


回答3:

if and grep -E more portable solution

For portability, I recommend that you just use if statements and grep -E which supports extended regular expressions, e.g.:

arg='abc'
if echo "$arg" | grep -Eq 'a.c|d.*'; then
  echo 'first'
elif echo "$arg" | grep -Eq 'a{2,3}'; then
  echo 'second'
fi

POSIX 7

Bash appears to follow POSIX by default without shopt as mentioned by https://stackoverflow.com/a/4555979/895245

Here is the quote: http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_01 section "Case Conditional Construct":

The conditional construct case shall execute the compound-list corresponding to the first one of several patterns (see Pattern Matching Notation) [...] Multiple patterns with the same compound-list shall be delimited by the '|' symbol. [...]

The format for the case construct is as follows:

case word in
     [(] pattern1 ) compound-list ;;
     [[(] pattern[ | pattern] ... ) compound-list ;;] ...
     [[(] pattern[ | pattern] ... ) compound-list]
  esac

and then http://pubs.opengroup.org/onlinepubs/9699919799/utilities/V3_chap02.html#tag_18_13 section "2.13. Pattern Matching Notation" only mentions ?, * and [].