I'm trying to send a vector as an argument to a function and i can't figure out how to make it work. Tried a bunch of different ways but they all give different error messages.
I only include part of the code, since it's only this part that doesn't work.
(the vector "random" is filled with random, but sorted, values between 0 and 200)
Updated the code:
#include <iostream>
#include <ctime>
#include <algorithm>
#include <vector>
using namespace std;
int binarySearch(int first, int last, int search4, vector<int>& random);
int main()
{
vector<int> random(100);
int search4, found;
int first = 0;
int last = 99;
found = binarySearch(first, last, search4, random);
system("pause");
return(0);
}
int binarySearch(int first, int last, int search4, vector<int>& random)
{
do
{
int mid = (first + last) / 2;
if (search4 > random[mid])
first = mid + 1;
else if (search4 < random[mid])
last = mid - 1;
else
return mid;
} while (first <= last);
return -(first + 1);
}
It depends on if you want to pass the vector
as a reference or as a pointer (I am disregarding the option of passing it by value as clearly undesirable).
As a reference:
int binarySearch(int first, int last, int search4, vector<int>& random);
vector<int> random(100);
// ...
found = binarySearch(first, last, search4, random);
As a pointer:
int binarySearch(int first, int last, int search4, vector<int>* random);
vector<int> random(100);
// ...
found = binarySearch(first, last, search4, &random);
Inside binarySearch
, you will need to use .
or ->
to access the members of random
correspondingly.
Issues with your current code
binarySearch
expects a vector<int>*
, but you pass in a vector<int>
(missing a &
before random
)
- You do not dereference the pointer inside
binarySearch
before using it (for example, random[mid]
should be (*random)[mid]
- You are missing
using namespace std;
after the <include>
s
- The values you assign to
first
and last
are wrong (should be 0 and 99 instead of random[0]
and random[99]
You'll have to pass the pointer to the vector, not the vector itself. Note the additional '&' here:
found = binarySearch(first, last, search4, &random);
You're passing in a pointer *random
but you're using it like a reference &random
The pointer (what you have) says "This is the address in memory that contains the address of random"
The reference says "This is the address of random"
Anytime you're tempted to pass a collection (or pointer or reference to one) to a function, ask yourself whether you couldn't pass a couple of iterators instead. Chances are that by doing so, you'll make your function more versatile (e.g., make it trivial to work with data in another type of container when/if needed).
In this case, of course, there's not much point since the standard library already has perfectly good binary searching, but when/if you write something that's not already there, being able to use it on different types of containers is often quite handy.
found = binarySearch(first, last, search4, &random);
Notice the &
.
You're using the argument as a reference but actually it's a pointer. Change vector<int>*
to vector<int>&
. And you should really set search4
to something before using it.
If you use random
instead of * random
your code not give any error