Making a Sass mixin with optional arguments

问题:

I am writing a mixin like this:

@mixin box-shadow($top, $left, $blur, $color, $inset:"") {
    -webkit-box-shadow: $top $left $blur $color $inset;
    -moz-box-shadow: $top $left $blur $color $inset;
    box-shadow: $top $left $blur $color $inset;
}

When called what I really want is that if no $inset value is passed, nothing is output, rather than it compiling to something like this:

-webkit-box-shadow: 2px 2px 5px #555555 "";
-moz-box-shadow: 2px 2px 5px #555555 "";
box-shadow: 2px 2px 5px #555555 "";

How do I rewrite the mixin so that if there is no value of $inset passed, nothing is output?

回答1:

A DRY'r Way of Doing It

And, generally, a neat trick to remove the quotes.

@mixin box-shadow($top, $left, $blur, $color, $inset:"") {
  -webkit-box-shadow: $top $left $blur $color #{$inset};
  -moz-box-shadow:    $top $left $blur $color #{$inset};
  box-shadow:         $top $left $blur $color #{$inset};
}

SASS Version 3+, you can use unquote():

@mixin box-shadow($top, $left, $blur, $color, $inset:"") {
  -webkit-box-shadow: $top $left $blur $color unquote($inset);
  -moz-box-shadow:    $top $left $blur $color unquote($inset);
  box-shadow:         $top $left $blur $color unquote($inset);
} 

Picked this up over here: pass a list to a mixin as a single argument with SASS

回答2:

A so much better DRY way

is to pass $args... to the @mixin. That way, no matter how many $args you will pass. In the @input call, you can pass all args needed. Like so:

@mixin box-shadow($args...) {
  -webkit-box-shadow: $args;
  -moz-box-shadow: $args;
  box-shadow: $args;
}

And now you can reuse your box-shadow in every class you want by passing all needed args:

.my-box-shadow {
  @include box-shadow(2px 2px 5px #555, inset 0 0 0);
}

回答3:

Sass supports @if statements. (See the documentation.)

You could write your mixin like this:

@mixin box-shadow($top, $left, $blur, $color, $inset:"") {
  @if $inset != "" {
    -webkit-box-shadow:$top $left $blur $color $inset;
    -moz-box-shadow:$top $left $blur $color $inset;
    box-shadow:$top $left $blur $color $inset;
  }
}

回答4:

You can put the property with null as a default value and if you don't pass the parameter it will not be interpreted.

@mixin box-shadow($top, $left, $blur, $color, $inset:null) {
  -webkit-box-shadow: $top $left $blur $color $inset;
  -moz-box-shadow:    $top $left $blur $color $inset;
  box-shadow:         $top $left $blur $color $inset;
}

This means you can write the include statement like this.

@include box-shadow($top, $left, $blur, $color);

Instead of writing it like this.

@include box-shadow($top, $left, $blur, $color, null);

As shown in the answer here

回答5:

Old question, I know, but I think this is still relevant. Arguably, a clearer way of doing this is to use the unquote() function (which SASS has had since version 3.0.0):

@mixin box-shadow($top, $left, $blur, $color, $inset:"") {
  -webkit-box-shadow: $top $left $blur $color unquote($inset);
  -moz-box-shadow: $top $left $blur $color unquote($inset);
  box-shadow: $top $left $blur $color unquote($inset);
}

This is roughly equivalent to Josh's answer, but I think the explicitly named function is less obfuscated than the string interpolation syntax.

回答6:

I know its not exactly the answer you were searching for but you could pass "null" as last argument when @include box-shadow mixin, like this @include box-shadow(12px, 14px, 2px, green, null); Now, if that argument is only one in that property than that property (and its (default) value) won't get compiled. If there are two or more args on that "line" only ones that you nulled won't get compiled (your case).

CSS output is exactly as you wanted it, but you have to write your nulls :)

  @include box-shadow(12px, 14px, 2px, green, null);

  // compiles to ...

  -webkit-box-shadow: 12px 14px 2px green;  
  -moz-box-shadow: 12px 14px 2px green;  
  box-shadow: 12px 14px 2px green;

回答7:

here is the solution i use, with notes below:

@mixin transition($trans...) {
  @if length($trans) < 1 {
    $trans: all .15s ease-out;
  }
  -moz-transition: $trans;
  -ms-transition: $trans;
  -webkit-transition: $trans;
  transition: $trans;
}

.use-this {
  @include transition;
}

.use-this-2 {
  @include transition(all 1s ease-out, color 2s ease-in);
}

• prefer passing property values as native css to stay close to "the tongue"
• allow passing variable number of arguments
• define a default value for laziness

回答8:

With sass@3.4.9 :

// declare
@mixin button( $bgcolor:blue ){
    background:$bgcolor;
}

and use without value, button will be blue

//use
.my_button{
    @include button();
}

and with value, button will be red

//use
.my_button{
    @include button( red );
}

works with hexa too

回答9:

Even DRYer way!

@mixin box-shadow($args...) {
  @each $pre in -webkit-, -moz-, -ms-, -o- {
    #{$pre + box-shadow}: $args;
  } 
  #{box-shadow}: #{$args};
}

And now you can reuse your box-shadow even smarter:

.myShadow {
  @include box-shadow(2px 2px 5px #555, inset 0 0 0);
}

回答10:

@mixin box-shadow($left: 0, $top: 0, $blur: 6px, $color: hsla(0,0%,0%,0.25), $inset: false) {
    @if $inset {
        -webkit-box-shadow: inset $left $top $blur $color;
        -moz-box-shadow: inset $left $top $blur $color;
        box-shadow: inset $left $top $blur $color;
    } @else {
        -webkit-box-shadow: $left $top $blur $color;
        -moz-box-shadow: $left $top $blur $color;
        box-shadow: $left $top $blur $color;
    }
}

回答11:

Super simple way

Just add a default value of none to $inset - so

@mixin box-shadow($top, $left, $blur, $color, $inset: none) { ....

Now when no $inset is passed nothing will be displayed.

回答12:

I am new to css compilers, hope this helps,

        @mixin positionStyle($params...){

            $temp:nth($params,1);
            @if $temp != null{
            position:$temp;
            }

             $temp:nth($params,2);
            @if $temp != null{
            top:$temp;
            }

             $temp:nth($params,3);
            @if $temp != null{
            right:$temp;
            }

             $temp:nth($params,4);
            @if $temp != null{
            bottom:$temp;
            }

            $temp:nth($params,5);
            @if $temp != null{
            left:$temp;
            }

    .someClass{
    @include positionStyle(absolute,30px,5px,null,null);
    }

//output

.someClass{
position:absolute;
 top: 30px;
 right: 5px;
}

回答13:

You can always assign null to your optional arguments. Here is a simple fix

@mixin box-shadow($top, $left, $blur, $color, $inset:null) { //assigning null to inset value makes it optional
    -webkit-box-shadow: $top $left $blur $color $inset;
    -moz-box-shadow: $top $left $blur $color $inset;
    box-shadow: $top $left $blur $color $inset;
}