Sorting multiple keys with Unix sort

问题:

I have potentially large files that need to be sorted by 1-n keys. Some of these keys might be numeric and some of them might not be. This is a fixed-width columnar file so there are no delimiters.

Is there a good way to do this with Unix sort? With one key it is as simple as using '-n'. I have read the man page and searched Google briefly, but didn't find a good example. How would I go about accomplishing this?

Note: I have ruled out Perl because of the file size potential. It would be a last resort.

回答1:

Use the -k option (or --key=POS1[,POS2]). It can appear multiple times and each key can have global options (such as n for numeric sort)

回答2:

Take care though:

If you want to sort the file primarily by field 3, and secondarily by field 2 you don't want this:

sort -k 3 -k 2 < inputfile

you want this instead:

sort -k 3,3 -k 2,2 < inputfile

The first one sorts the file by the string from the beginning of field 3 to the end of line (which is potentially unique).

-k, --key=POS1[,POS2]     start a key at POS1 (origin 1), end it at POS2
                          (default end of line)

回答3:

The -k option is what you want.

-k 1.4,1.5n -k 1.14,1.15n

Would use character positions 4-5 in the first field (it's all one field for fixed width) and sort numerically as the first key.

The second key would be characters 14-15 in the first field also.

(edit)

Example (all I have is DOS/cygwin handy):

dir | \cygwin\bin\sort.exe -k 1.4,1.5n -k 1.40,1.60r

for the data:

12/10/2008  01:10 PM         1,564,990 outfile.txt

Sorts the directory listing by month number (pos 4-5) numerically, and then by filename (pos 40-60) in reverse. Since there are no tabs, it's all field 1 to sort.

回答4:

Here is one to sort various columns in a csv file by numeric and dictionary order, columns 5 and after as dictionary order

~/test>sort -t, -k1,1n -k2,2n -k3,3d -k4,4n -k5d  sort.csv
1,10,b,22,Ga
2,2,b,20,F
2,2,b,22,Ga
2,2,c,19,Ga
2,2,c,19,Gb,hi
2,2,c,19,Gb,hj
2,3,a,9,C

~/test>cat sort.csv
2,3,a,9,C
2,2,b,20,F
2,2,c,19,Gb,hj
2,2,c,19,Gb,hi
2,2,c,19,Ga
2,2,b,22,Ga
1,10,b,22,Ga

Note the -k1,1n means numeric starting at column 1 and ending at column 1. If I had done below, it would have concatenated column 1 and 2 making 1,10 sorted as 110

~/test>sort -t, -k1,2n -k3,3 -k4,4n -k5d  sort.csv
2,2,b,20,F
2,2,b,22,Ga
2,2,c,19,Ga
2,2,c,19,Gb,hi
2,2,c,19,Gb,hj
2,3,a,9,C
1,10,b,22,Ga

回答5:

I believe in your case something like

sort -t@ -k1.1,1.4 -k1.5,1.7 ... <inputfile

will work better. @ is the field separator, make sure it is a character that appears nowhere. then your input is considered as consisting of one column.

Edit: apparently clintp already gave a similar answer, sorry. As he points out, the flags 'n' and 'r' can be added to every -k.... option.

回答6:

Note that is may also be desired to stabilize the sort with the -s switch, so that equally ranked lines maintain their original relative order in the output too.

回答7:

I just want to add some tips, when you using sort , be careful about your locale that effects the order of the key comparison. I usually explicitly use LC_ALL=C to make locale what I want.