Stack Overflow error occurs when using recursive f

问题:

Here's my code and it runs well with values of 400 to 4000 but once it's about 4mil, I get stack overflow errors.

Thanks in advance!

public class Fib {
static int c=1,b=2;
static long sum1=0,sum2=0;

static long fib(long a){
if(a==1){
    return 1;
}
if(a==2){
    return 2;
}
else{
    return fib(a-1)+fib(a-2);
}

    }


    public static void main(String[] args){
sum2= fib(4000000);
    System.out.println("Sum %f" +sum2);
}
    }

回答1:

Yes - you're running out of stack space. It's far from infinite, and you're using it up on each recursive call. You're trying to end up with a stack with 4 million stack frames - that's not going to work.

I suggest you consider an iterative approach. Even if you had an infinite amount of stack, that code would probably not complete before the heat death of the universe. (Think about the complexity of this code...)

回答2:

You can increase the stack size of Java programs. Example:

java -Xss4m YourProgram

Reference

Nevertheless I would also recommend an iterative method.

回答3:

As Jon Skeet above mentioned, your code would require a huge amount of time to run - 2 to the 4 million, which is not practical in any way. Frankly i'm surprised the stack ran dry at all, I'd think the code would just run for a ridiculous amount of time.

You should use an iterative approach. Here's a nicer implementation of the fibonacci sequence:

static long fib(long i){
    if ( i == 0 || i == 1 ) return 1;
    long a = 1; //This is the 0th element 
    long b = 1; //This is the 1st element
    while( i-- > 1 ){ //Each iteration, sets a and b to the next element in the fibonacci sequence
        long temp = b;
        a += b;
        b = a;
        a = temp;
    }
    return b;
}