I'm reviving this question, and making it more specific: Is there a .NET framework library that supports numbers with arbitrary digits of precision?
问题:
回答1:
There are a few options here.
A good option is W3b.Sine, which is native C#/.NET, and supports arbitrary precision floating point values.
If you are only dealing with integer values, IntX provides support for arbitrary precision integer values. A potentially more mature option would be C# BigInt, but again, this will not support floating point operations.
回答2:
Can you wait for .NET 4.0? They're bringing BigInteger directly into the Framework.
On the other hand, if you can't wait, then the J# runtime includes built-in support for java.math.BigInteger and BigDecimal. This is redistributable just like the rest of the .NET Framework.
回答3:
You could try the old method of mantissa. Basically you could have an 64 bit integer for storing the number and then a 64 bit integer for storing the exponent (which could be negative). You could build your own object type and overload the arithmetic operators, so it will be treated as a single number. It will require some work, but I think it will be your best option.
回答4:
GnuMpDotNet: http://www.emilstefanov.net/Projects/GnuMpDotNet/
If you need pure .NET consider looking into this: http://www.codeplex.com/IntX/
回答5:
Perhaps surprisingly, the Bailey-Borwein-Plouffe formula gives an incremental procedure for computing the next binary or hexadecimal digit of pi without needing to store all the previous digits.
回答6:
If you want a really fast library then try:
http://www.emilstefanov.net/Projects/GnuMpDotNet/
回答7:
You can use decimal type which gives you 28-29 significant digits
回答8:
Check this link http://jsfromhell.com/classes/bignumber
its a javascript code but you can easily convert it to your own in any language or in C#.
回答9:
Here is a good article on how to represent infinite digits.
http://dobbscodetalk.com/index.php?option=com_myblog&show=Basic-Arithmetic-with-Infinite-Integers.html&Itemid=29
good luck