Remove specific characters inside parentheses usin

问题:

I have a line like this:

BlockedMatch(XA, YB), Correlation(XA, QC), Correlation(YB, QC), Correlation(QC, YB)

I want it to look like this:

BlockedMatch(XAYB), Correlation(XAQC), Correlation(YBQC), Correlation(QCYB)

I can't just do a replace on ", " because it will remove those instances that exist outside of the parentheses.

I tried this:

replaceAll("\\((.*?)\\)", "")

which replaces everything inside the parentheses (not just the comma). I've tried to add just the comma and space combination into that regex, but it doesn't seem to remove anything then.

Could someone show me how to specify to only remove the ", " (comma-space) when it occurs inside parentheses?

回答1:

Use a look ahead:

str = str.replaceAll(", (?=[^(]*\\))", "");

This regex says "replace the comma-space only when the next bracket character is a close bracket"

---

Some test code:

String str = "BlockedMatch(XA, YB), Correlation(XA, QC), Correlation(YB, QC), Correlation(QC, YB)";
str = str.replaceAll(", (?=[^(]*\\))", "");
System.out.println(str);

Output:

BlockedMatch(XAYB), Correlation(XAQC), Correlation(YBQC), Correlation(QCYB)

回答2:

The safest way to do this is to use two regexes: First, capture all (...) and from those results, remove all commas and optional whitespace.

For your specific case, you can search , *([^()]*)(?=\)) and replace with \1 which you can see here.

This may have issues with edge cases where you have multiple things within your parentheses that you wish to remove (such as (XA, YB, ZC)).

Or (without replacing) search for , *(?=[^(]*\)) and replace with (nothing) which you can see here. This handles multiple , fairly well, but will have problems if you have embedded (...) characters.

回答3:

You can do it with a simple word-boundary since the commas you want to avoid are preceded by a closing parenthesis and the commas you want to match are preceded by a letter:

str = str.replaceAll("\\b, ", "");

回答4:

You can use:

String s = "BlockedMatch(XA, YB), Correlation(XA, QC), Correlation(YB, QC), Correlation(QC, YB)";
Pattern p = Pattern.compile("(\\([^)]+\\))");
Matcher mat = p.matcher(s);
StringBuffer sb = new StringBuffer();
while (mat.find()) {
    mat.appendReplacement(sb, mat.group(1).replaceAll(" *, *", ""));
}
mat.appendTail(sb);
System.out.println(sb);

Output:

BlockedMatch(XAYB), Correlation(XAQC), Correlation(YBQC), Correlation(QCYB)