Fill a vector with weekdays only

2019-01-28 04:17发布

问题:

I know the start date start and the last date maturity. How can I fill in a vector with dates without taking weekends dates into account ? For instance, let's say :

> start = as.Date("2013-02-28");
> maturity = as.Date("2013-03-07");

I would like to get the following vector as a result :

results
[1] "2013-03-01" "2013-03-04" "2013-03-05" "2013-03-06" "2013-03-07"



> start = as.Date("2013-02-28");
> maturity = as.Date("2013-03-07");
> x <- seq(start,maturity,by = 1)
> x
[1] "2013-02-28" "2013-03-01" "2013-03-02" "2013-03-03" "2013-03-04" "2013-03-05"
[7] "2013-03-06" "2013-03-07"
> x <- x[!weekdays(x) %in% c('Saturday','Sunday')]
> x
[1] "2013-02-28" "2013-03-01" "2013-03-02" "2013-03-03" "2013-03-04" "2013-03-05"
[7] "2013-03-06" "2013-03-07"

Same results... ?

回答1:

There are probably a billion ways to do this with a variety of functions from multiple packages. But my first thought is to simply make a sequence and then remove the weekends:

x <- seq(as.Date('2011-01-01'),as.Date('2011-12-31'),by = 1)
x <- x[!weekdays(x) %in% c('Saturday','Sunday')]

This answer is valid only with an English based system. For instance, in a French version, 'Saturday' and 'Sunday' must be translated into 'samedi' and 'dimanche'



回答2:

This less human than @joran answer:) , but it is no local-time depending

dd <- seq(as.Date('2011-01-01'),as.Date('2011-12-31'),by = 1)
dd[! (as.POSIXlt(dd)$wd %in% c(0,1))]

PS : another option , is to set locals before applying weekdays

tt <- Sys.getlocale('LC_TIME')
Sys.setlocale('LC_TIME','ENGLISH')
dd <- dd[!weekdays(x) %in% c('Saturday','Sunday')]
Sys.setlocale('LC_TIME',tt)


标签: r date vector