I'm trying to use a function in order to get this working:
<img src='login.php?image=ind_legend.jpg'>
But I can't pass through the function to place the image. I went back a couple of steps and tried only this part of the code:
<?php
$file = "http://localhost/sales/test.jpg";
header('Content-type: image/jpeg');
readfile($file);
?>
or using this function:
echo file_get_contents($source);
but the fact is that the only thing I get is a broken image cross (IE) or nothing in Firefox.
I would appreciate any suggestions
Thanks in advance
You certainly have some whitespace in your PHP script, or a UTF-8 BOM
invisibly before your <?php
opening marker. Use a hexeditor to find out.
To debug it further, open the image URL http://localhost/login.php?image=ind_legend.jpg directly in your browser, save the file. And then compare it to the original JPEG.
use the ob_clean() function of php before the readfile()
As previously mentioned, you probably have some whitespace. I'd try replacing the entire file with the code below. Removing the closing php statement eliminates any chance that there is extra whitespace:
<?php
$file = "http://localhost/sales/test.jpg";
header('Content-type: image/jpeg');
readfile($file);
first of all point your browser to http://youraddress/login.php?image=ind_legend.jpg and check the result.
Maybe the file /sales/test.jpg is corrupted or you don't have enabled the http:// wrapper for readline
At last save the corrupted image via the save image as... context menu option of your browser of choice and try to open it with a text editor. I will not surprised if you will find an error message (if you have them enabled).