I have an array in this format:
Array
(
[0] => Array
(
[id] => 117
[name] => Networking
[count] => 16
)
[1] => Array
(
[id] => 188
[name] => FTP
[count] => 23
)
[2] => Array
(
[id] => 189
[name] => Internet
[count] => 48
)
)
Is there a good way to retrieve the minimum and maximum values of 'count'? I could do this using a few loops but I thought there may be a better way.
In contrast to what others have posted, you cannot use the min()
/max()
functions for this problem as these functions do not understand the datastructure (array) which are passed in. These functions only work for scalar array elements.
BEGIN EDIT
The reason why the use of min()
and max()
seem to yield the correct answer is related to type-casting arrays to integers which is an undefined behaviour:
The behaviour of converting to integer
is undefined for other types. Do not
rely on any observed behaviour, as it
can change without notice.
My statement above about the type-casting was wrong. Actually min()
and max()
do work with arrays but not in the way the OP needs them to work. When using min()
and max()
with multiple arrays or an array of arrays elements are compared element by element from left to right:
$val = min(array(2, 4, 8), array(2, 5, 1)); // array(2, 4, 8)
/*
* first element compared to first element: 2 == 2
* second element compared to second element: 4 < 5
* first array is considered the min and is returned
*/
Translated into the OP's problem this shows the reason why the direct use of min()
and max()
seems to yield the correct result. The arrays' first elements are the id
-values, therefore min()
and max()
will compare them first, incidentally resulting in the correct result because the lowest id
is the one with the lowest count
and the highest id
is the one with the highest count
.
END EDIT
The correct way would be to use a loop.
$a = array(
array('id' => 117, 'name' => 'Networking', 'count' => 16),
array('id' => 188, 'name' => 'FTP', 'count' => 23),
array('id' => 189, 'name' => 'Internet', 'count' => 48)
);
$min = PHP_INT_MAX;
$max = 0;
foreach ($a as $i) {
$min = min($min, $i['count']);
$max = max($max, $i['count']);
}
You could use the max() and min() functions.
What did you do with a few loops? One is quite enough :)
- Get the first element, assing the count to both $min and $max
- iterate over the rest, compare count to each $min and $max, if smaller/larger, assign the new count value
You can use the max
/min
functions as they will return an array containing the maximum/minimum of each index. Your example should return array(189, 'Networking
', 48)
for max
. You could then grab the count from that array.
Update this doesn't work as I had excepted. The manual page example is misleading and the example about gives the correct result using max but that is just a coincidence.
Looks like you can't use max() on a 2D array. It just returns the largest array, not the max() of each index (as being mentioned in a few answers).
So:
$count = array();
foreach($arr as $_arr) {
$count[] = $_arr['count'];
}
var_dump(max($count), min($count));
Is there an equivalent build-in function to that one?
(even without the test capability)
/**
* extracts a column from a 2D array, with an optional selection over another column
*
* @param $aArray array to extract from
* @param $aColName name of the column to extract, ex. 'O_NAME'
* @param $aColTest (optional) name of the column to make the test on, ex. 'O_ID'
* @param $aTest (optional) string for the test ex. ">= 10", "=='".$toto."'"
* @return 1D array with only the extracted column
* @access public
*/
function extractColFromArray($aArray, $aColName, $aColTest="", $aTest="") {
$mRes = array();
foreach($aArray as $row) {
if (($aColTest == "") || (eval("return " . $row[$aColTest] . $aTest . ";" )) ) {
$mRes[] = $row[$aColName];
}
}
return $mRes;
} // extractColFromArray
If the desired column is first in the array you can use the following one-liners:
$max = max(array_map('current', $a));
$min = min(array_map('current', $a));
This will find the min/max of id