问题:

Possible Duplicate:
What does this ~ operator mean here?
Bit not operation in PHP(or any other language probably)

Can someone explain me the ~ operator in PHP? I know it's a NOT-operator, but why does PHP convert following statement to the negative value of the variable minus one?

$a = 1; echo ~$a    // echo -2
$a = 2; echo ~$a    // echo -3
$a = 3; echo ~$a    // echo -4

回答1:

This is called the two's complement arithmetic. You can read about it in more detail here.

The operator ~ is a binary negation operator (as opposed to boolean negation), and being that, it inverses all the bits of its operand. The result is a negative number in two's complement arithmetic.

回答2:

It's a bitwise NOT.

It converts all 1s to 0s, and all 0s to 1s. So 1 becomes -2 (0b111111111110 in binary representation).

Have a look at the doc http://php.net/manual/en/language.operators.bitwise.php

回答3:

~ flips all the bits of the number. In two's complement (google it), mathematical negation is achievable by flipping all the bits and then adding 1. If you only do the first step (ie: just flip the bits), you have the additive inverse minus 1.