Android camera intent

问题:

I need to push an intent to default camera application to make it take a photo, save it and return an URI. Is there any way to do this?

回答1:

private static final int TAKE_PICTURE = 1;    
private Uri imageUri;

public void takePhoto(View view) {
    Intent intent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
    File photo = new File(Environment.getExternalStorageDirectory(),  \"Pic.jpg\");
    intent.putExtra(MediaStore.EXTRA_OUTPUT,
            Uri.fromFile(photo));
    imageUri = Uri.fromFile(photo);
    startActivityForResult(intent, TAKE_PICTURE);
}

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);
    switch (requestCode) {
    case TAKE_PICTURE:
        if (resultCode == Activity.RESULT_OK) {
            Uri selectedImage = imageUri;
            getContentResolver().notifyChange(selectedImage, null);
            ImageView imageView = (ImageView) findViewById(R.id.ImageView);
            ContentResolver cr = getContentResolver();
            Bitmap bitmap;
            try {
                 bitmap = android.provider.MediaStore.Images.Media
                 .getBitmap(cr, selectedImage);

                imageView.setImageBitmap(bitmap);
                Toast.makeText(this, selectedImage.toString(),
                        Toast.LENGTH_LONG).show();
            } catch (Exception e) {
                Toast.makeText(this, \"Failed to load\", Toast.LENGTH_SHORT)
                        .show();
                Log.e(\"Camera\", e.toString());
            }
        }
    }
}

回答2:

Try the following I found here

Intent intent = new Intent(\"android.media.action.IMAGE_CAPTURE\");
startActivityForResult(intent, 0);

@Override
public void onActivityResult(int requestCode, int resultCode, Intent data) {
  if (resultCode == Activity.RESULT_OK && requestCode == 0) {
    String result = data.toURI();
    // ...
  }
}

回答3:

It took me some hours to get this working. The code it\'s almost a copy-paste from developer.android.com, with a minor difference.

Request this permission on the AndroidManifest.xml:

<uses-permission android:name=\"android.permission.WRITE_EXTERNAL_STORAGE\" />

On your Activity, start by defining this:

static final int REQUEST_IMAGE_CAPTURE = 1;
private Bitmap mImageBitmap;
private String mCurrentPhotoPath;
private ImageView mImageView;

Then fire this Intent in an onClick:

Intent cameraIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
if (cameraIntent.resolveActivity(getPackageManager()) != null) {
    // Create the File where the photo should go
    File photoFile = null;
    try {
        photoFile = createImageFile();
    } catch (IOException ex) {
        // Error occurred while creating the File
        Log.i(TAG, \"IOException\");
    }
    // Continue only if the File was successfully created
    if (photoFile != null) {
        cameraIntent.putExtra(MediaStore.EXTRA_OUTPUT, Uri.fromFile(photoFile));
        startActivityForResult(cameraIntent, REQUEST_IMAGE_CAPTURE);
    }
}

Add the following support method:

private File createImageFile() throws IOException {
    // Create an image file name
    String timeStamp = new SimpleDateFormat(\"yyyyMMdd_HHmmss\").format(new Date());
    String imageFileName = \"JPEG_\" + timeStamp + \"_\";
    File storageDir = Environment.getExternalStoragePublicDirectory(
            Environment.DIRECTORY_PICTURES);
    File image = File.createTempFile(
            imageFileName,  // prefix
            \".jpg\",         // suffix
            storageDir      // directory
    );

    // Save a file: path for use with ACTION_VIEW intents
    mCurrentPhotoPath = \"file:\" + image.getAbsolutePath();
    return image;
}

Then receive the result:

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    if (requestCode == REQUEST_IMAGE_CAPTURE && resultCode == RESULT_OK) {
        try {
            mImageBitmap = MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.parse(mCurrentPhotoPath));
            mImageView.setImageBitmap(mImageBitmap);
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}

What made it work is the MediaStore.Images.Media.getBitmap(this.getContentResolver(), Uri.parse(mCurrentPhotoPath)), which is different from the code from developer.android.com. The original code gave me a FileNotFoundException.

回答4:

Try the following I found Here\'s a link

If your app targets M and above and declares as using the CAMERA permission which is not granted, then attempting to use this action will result in a SecurityException.

EasyImage.openCamera(Activity activity, int type);

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) {
    super.onActivityResult(requestCode, resultCode, data);

    EasyImage.handleActivityResult(requestCode, resultCode, data, this, new DefaultCallback() {
        @Override
        public void onImagePickerError(Exception e, EasyImage.ImageSource source, int type) {
            //Some error handling
        }

        @Override
        public void onImagesPicked(List<File> imagesFiles, EasyImage.ImageSource source, int type) {
            //Handle the images
            onPhotosReturned(imagesFiles);
        }
    });
}

回答5:

I found a pretty simple way to do this. Use a button to open it using an on click listener to start the function openc(), like this:

String fileloc;
private void openc()
{
    Intent takePictureIntent = new Intent(MediaStore.ACTION_IMAGE_CAPTURE);
    File f = null;
    try 
    {
        f = File.createTempFile(\"temppic\",\".jpg\",getApplicationContext().getCacheDir());
        if (takePictureIntent.resolveActivity(getPackageManager()) != null)
        {               
            takePictureIntent.putExtra(MediaStore.EXTRA_OUTPUT,FileProvider.getUriForFile(profile.this, BuildConfig.APPLICATION_ID+\".provider\",f));
            fileloc = Uri.fromFile(f)+\"\";
            Log.d(\"texts\", \"openc: \"+fileloc);
            startActivityForResult(takePictureIntent, 3);
        }
    } 
    catch (IOException e) 
    {
        e.printStackTrace();
    }
}

@Override
protected void onActivityResult(int requestCode, int resultCode, Intent data) 
{
    super.onActivityResult(requestCode, resultCode, data);
    if(requestCode == 3 && resultCode == RESULT_OK) {
        Log.d(\"texts\", \"onActivityResult: \"+fileloc);
        // fileloc is the uri of the file so do whatever with it
    }
}

You can do whatever you want with the uri location string. For instance, I send it to an image cropper to crop the image.

回答6:

try this code

Intent photo= new Intent(\"android.media.action.IMAGE_CAPTURE\");
                    startActivityForResult(photo, CAMERA_PIC_REQUEST);