converting an array of null terminated const char*

问题:

I have a Visual Studio 2008 C++ function where I'm given an array of null-terminated strings const char* and a count of the number of strings in that array.

I'm looking for a clever way of turning an array of const char* in to a std::vector< std::string >

/// @param count - number of strings in the array
/// @param array - array of null-terminated strings
/// @return - a vector of stl strings
std::vector< std::string > Convert( int count, const char* array[] );

Boost is fine, STL is fine.

Thanks, PaulH

回答1:

Something like this?:

vector< string > ret( array, array + count );

回答2:

Try this:

#include <string>
#include <vector>
#include <iterator>
#include <algorithm>
#include <iostream>


int main(int argc,char* argv[])
{
    // Put it into a vector
    std::vector<std::string>    data(argv, argv + argc);

    // Print the vector to std::cout
    std::copy(data.begin(), data.end(), std::ostream_iterator<std::string>(std::cout, "\n"));
}

回答3:

Assuming that the signature of your function is inadvertently wrong, do you mean something like this?

#include <algorithm>
#include <iterator>
#include <string>
#include <vector>

std::vector<std::string> Convert(int count, const char **arr)
{
    std::vector<std::string> vec;
    vec.reserve(count);
    std::copy(arr, arr+count, std::back_inserter(vec));
    return vec;
}

int main()
{
    const char *arr[3] = {"Blah", "Wibble", "Shrug"};
    std::vector<std::string> vec = Convert(3, arr);
    return 0;
}

回答4:

I assume in your array strings are separated by 0s.

std::vector< std::string > Convert( int count, const char* array )
{
   std::vector< std::string > result;

   for(const char* begin = array; count; --count)
   {
    const char* end = begin;
    for(; *end; ++end);
    result.push_back(std::string(begin, end));
    begin = end + 1;
   }

   return result;
}