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问题:
I am trying to make a lottery program for my school (we have an economic system).
My program generates numbers and saves it off into a text file. When I want to "pull" numbers out of my generator I want it to ensure that there is a winner.
Q: How do I have Python select a random line out of my text file and give my output as that number?
回答1:
How do I have python select a random line out of my text file and give my output as that number?
Assuming the file is relatively small, the following is perhaps the easiest way to do it:
import random
line = random.choice(open('data.txt').readlines())
回答2:
If the file is very large - you could seek to a random location in the file given the file size and then get the next full line:
import os, random
def get_random_line(file_name):
total_bytes = os.stat(file_name).st_size
random_point = random.randint(0, total_bytes)
file = open(file_name)
file.seek(random_point)
file.readline() # skip this line to clear the partial line
return file.readline()
回答3:
def random_line():
line_num = 0
selected_line = ''
with open(filename) as f:
while 1:
line = f.readline()
if not line: break
line_num += 1
if random.uniform(0, line_num) < 1:
selected_line = line
return selected_line.strip()
Although most of the approaches given here would work, but they tend to load the whole file in the memory at once. But not this approach. So even if the files are big, this would work.
The approach is not very intuitive at first glance. The theorem behind this states that when we have seen N lines in there is a probability of exactly 1/N that each of them is selected so far.
From Page no 123 of 'Python Cookbook'
回答4:
With a slight modification to your input file (store the number of items in the first line), you can choose a number uniformly without having to read the entire file into memory first.
import random
def choose_number( frame ):
with open(fname, "r") as f:
count = int(f.readline().strip())
for line in f:
if not random.randrange(0, count):
return int(line.strip())
count-=1
Say you have 100 numbers. The probability of choosing the first number is 1/100. The probability of choosing the second number is (99/100)(1/99) = 1/100. The probability of choosing the third number is (99/100)(98/99)(1/98) = 1/100. I'll skip the formal proof, but the odds of choosing any of the 100 numbers is 1/100.
It's not strictly necessary to store the count in the first line, but it saves you the trouble of having to read the entire file just to count the lines. Either way, you don't need to store the entire file in memory to choose any single line with equal probability.
回答5:
Off the top of my head:
import random
def pick_winner(self):
lines = []
with open("file.txt", "r") as f:
lines = f.readlines();
random_line_num = random.randrange(0, len(lines))
return lines[random_lines_num]
回答6:
another approach:
import random, fileinput
text = None
for line in fileinput.input('data.txt'):
if random.randrange(fileinput.lineno()) == 0:
text = line
print text
Distribution:
$ seq 1 10 > data.txt
# run for 100000 times
$ ./select.py > out.txt
$ wc -l out.txt
100000 out.txt
$ sort out.txt | uniq -c
10066 1
10004 10
10023 2
9979 3
9926 4
9936 5
9878 6
10023 7
10154 8
10011 9
I don't see the skewnes but perhaps the dataset is too small...
回答7:
I saw a python tutorials and found this snippet:
def randomLine(filename):
#Retrieve a random line from a file, reading through the file once
fh = open("KEEP-IMPORANT.txt", "r")
lineNum = 0
it = ''
while 1:
aLine = fh.readline()
lineNum = lineNum + 1
if aLine != "":
#
# How likely is it that this is the last line of the file ?
if random.uniform(0,lineNum)<1:
it = aLine
else:
break
nmsg=it
return nmsg
#this is suposed to be a var pull = randomLine(filename)