Can I escape braces in a java MessageFormat?

2019-01-25 01:25发布

问题:

I want to output some braces in a java MessageFormat. For example I know the following does not work:

MessageFormat.format("  public {0} get{1}() {return {2};}\n\n", type, upperCamel, lowerCamel);

Is there a way of escaping the braces surrounding "return {2}"?

回答1:

You can put them inside single quotes e.g.

'{'return {2};'}'

See here for more details.



回答2:

Wow. Surprise! The documentation for MessageFormat knows the answer:

Within a String, "''" represents a single quote. A QuotedString can contain arbitrary characters except single quotes; the surrounding single quotes are removed. An UnquotedString can contain arbitrary characters except single quotes and left curly brackets. Thus, a string that should result in the formatted message "'{0}'" can be written as "'''{'0}''" or "'''{0}'''".



回答3:

Use single quotes:

MessageFormat.format("  public {0} get{1}() '{'return {2};'}'\n\n",
                     type, upperCamel, lowerCamel);

If you want to actually use a single quote, just double it. The JavaDoc for MessageFormat gives this somewhat complicated example:

Thus, a string that should result in the formatted message "'{0}'" can be written as "'''{'0}''" or "'''{0}'''".

This is '' for a single quote, then '{' for an escaped brace, then 0, '}' for the closing brace and '' for the closing quote.



回答4:

System.out.println(MessageFormat.format("I want to see ticks and curly braces around '''{'{0}'}'''", "this"));


回答5:

you can use this regex with pearl or any other language to escape curly brackets and single quotes (x27). It does not touch any placeholder e.g. {0}: bash echo "# 'single' quote test \n\n public {0} get{1}() {return {2};}\n\n" | perl -pe 's/\x27/\x27\x27/g; s/\{([^0-9])/\x27\{\x27$1/g; s/([^0-9])\}/$1\x27\}\x27/g'