I have written an interface for accounting system access. I would like to hide specific implementations of the interface from my program as I will only ever have one "active" accounting system. So I planned on making the methods of the interface unexported (hidden), and then having exported functions native to the base package that call a the same function from a local adapter.
package accounting
import "errors"
type IAdapter interface {
getInvoice() error
}
var adapter IAdapter
func SetAdapter(a IAdapter) {
adapter = a
}
func GetInvoice() error {
if (adapter == nil) {
return errors.New("No adapter set!")
}
return adapter.getInvoice()
}
__________________________________________________
package accountingsystem
type Adapter struct {}
func (a Adapter) getInvoice() error {return nil}
__________________________________________________
package main
import (
"accounting"
"accountingsystem"
)
function main() {
adapter := accountingsystem.Adapter{}
accounting.SetAdapter(adapter)
}
The problem with this is that the compiler complains, due to not being able to see the implementation of getInvoice()
by accountingsystem.Adapter
:
./main.go:2: cannot use adapter (type accountingsystem.Adapter) as type accounting.IAdapter in argument to accounting.SetAdapter:
accountingsystem.Adapter does not implement accounting.IAdapter (missing accounting.getInvoice method)
have accountingsystem.getInvoice() error
want accounting.getInvoice() error
Is there any way of being able to implement an interface with unexported methods in another package? Or am I thinking about this problem in a non-idiomatic way?