I'm trying to attach a PDF file to my email sent with sendgrid.
Here is my code :
sg = sendgrid.SendGridAPIClient(apikey=os.environ.get('SENDGRID_API_KEY'))
from_email = Email("from@example.com")
subject = "subject"
to_email = Email("to@example.com")
content = Content("text/html", email_body)
pdf = open(pdf_path, "rb").read().encode("base64")
attachment = Attachment()
attachment.set_content(pdf)
attachment.set_type("application/pdf")
attachment.set_filename("test.pdf")
attachment.set_disposition("attachment")
attachment.set_content_id(number)
mail = Mail(from_email, subject, to_email, content)
mail.add_attachment(attachment)
response = sg.client.mail.send.post(request_body=mail.get())
print(response.status_code)
print(response.body)
print(response.headers)
But the Sendgrid Python library is throwing an error HTTP Error 400: Bad Request.
What is wrong with my code ?
I found a solution. I replaced this line :
pdf = open(pdf_path, "rb").read().encode("base64")
By this :
with open(pdf_path, 'rb') as f:
data = f.read()
encoded = base64.b64encode(data)
Now it works. I can send encoded file in the set_content :
attachment.set_content(encoded)
Note: The answer above works for Sendgrid v2 or lower. For v3 and up use:
encoded = base64.b64encode(data).decode()
This is my solution, Works with Sendgrid V3
# Where it was uploaded Path.
file_path = "MY_FILE_PATH"
with open(file_path, 'rb') as f:
data = f.read()
# Encode contents of file as Base 64
encoded = base64.b64encode(data).decode()
"""Build attachment"""
attachment = Attachment()
attachment.content = encoded
attachment.type = "application/pdf"
attachment.filename = "my_pdf_attachment.pdf"
attachment.disposition = "attachment"
attachment.content_id = "PDF Document file"
sg = sendgrid.SendGridAPIClient(apikey=settings.SENDGRID_API_KEY)
from_email = Email("origin@gmail.com")
to_email = Email('recipient@gmail.com')
content = Content("text/html", html_content)
mail = Mail(from_email, 'Attachment mail PDF', to_email, content)
mail.add_attachment(attachment)
try:
response = sg.client.mail.send.post(request_body=mail.get())
except urllib.HTTPError as e:
print(e.read())
exit()
Straight from the Sendgrid docs:
import urllib.request as urllib
import base64
import os
import json
from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import (Mail, Attachment, FileContent, FileName, FileType, Disposition, ContentId)
import os
import json
from sendgrid import SendGridAPIClient
from sendgrid.helpers.mail import Mail
message = Mail(
from_email='from_email@example.com',
to_emails='to@example.com',
subject='Sending with Twilio SendGrid is Fun',
html_content='<strong>and easy to do anywhere, even with Python</strong>')
file_path = 'example.pdf'
with open(file_path, 'rb') as f:
data = f.read()
f.close()
encoded = base64.b64encode(data).decode()
attachment = Attachment()
attachment.file_content = FileContent(encoded)
attachment.file_type = FileType('application/pdf')
attachment.file_name = FileName('test_filename.pdf')
attachment.disposition = Disposition('attachment')
attachment.content_id = ContentId('Example Content ID')
message.attachment = attachment
try:
sendgrid_client = SendGridAPIClient(os.environ.get('SENDGRID_API_KEY'))
response = sendgrid_client.send(message)
print(response.status_code)
print(response.body)
print(response.headers)
except Exception as e:
print(e.message)