If you have subdocument arrays, Mongoose automatically creates ids for each one. Example:
{
_id: \"mainId\"
subdocArray: [
{
_id: \"unwantedId\",
field: \"value\"
},
{
_id: \"unwantedId\",
field: \"value\"
}
]
}
Is there a way to tell Mongoose to not create ids for objects within an array?
It\'s simple, you can define this in the subschema :
var mongoose = require(\"mongoose\");
var subSchema = mongoose.Schema({
//your subschema content
},{ _id : false });
var schema = mongoose.Schema({
// schema content
subSchemaCollection : [subSchema]
});
var model = mongoose.model(\'tablename\', schema);
You can create sub-documents without schema and avoid _id. Just add _id:false to your subdocument declaration.
var schema = new mongoose.Schema({
field1:{type:String},
subdocArray:[{
_id:false,
field :{type:String}
}]
});
This will prevent the creation of an _id field in your subdoc. Tested in Mongoose 3.8.1
Additionally, if you use an object literal syntax for specifying a sub-schema, you may also just add _id: false
to supress it.
{
sub: {
property1: String,
property2: String,
_id: false
}
}
I\'m using mongoose 4.6.3 and all I had to do was add _id: false in the schema, no need to make a subschema.
{
_id: ObjectId
subdocArray: [
{
_id: false,
field: \"String\"
}
]
}
In mongoose v.3 now you have alternative way to create sub-documents without parents - children relations. And these sub-docs will not have index
var mongoose = require(\"mongoose\");
var schema = mongoose.Schema({
// schema content
subSchema: [{
firstname: \'sub name\',
lastname: \'last name\'
}]
});
var model = mongoose.model(\'tablename\', schema);