Why is the volatile field copied to a local variab

2019-01-23 21:01发布

问题:

I am reading about double check locking from Effective Java. The code does the following:

private volatile FieldType field;  
FieldType getField() {  
    FieldType result = field;  
    if (result == null) { // First check (no locking)  
        synchronized(this) {   
        result = field;  
        if (result == null) // Second check (with locking)  
            field = result = computeFieldValue();  
        }  
    }  
    return result;  
}    

It says that using result seems unneeded but actually ensures that the field is only read only once in the common case where it is already initialized.

But I don't understand this. What is the difference with doing if(field == null) directly? I don't understand why if (result == null) is different, let alone better as stated.

回答1:

The thinking in that example is that result/field will be used more than once further down I guess. Accessing result is cheaper (it's not volatile).

You have a second volatile read when doing the return otherwise.

Use the initializaton on demand holder pattern instead if you need to do this. http://en.wikipedia.org/wiki/Initialization_on_demand_holder_idiom

Adding some of my clarifications in the comments to the answer itself for well... clarity:

Short version: A local variable can just be in a register in (one of) the cpu(s) (and in one of the cpu's cores if multiple etc). That's as fast as it gets. A volatile variable must be checked for changes in other cores/caches/cpus/memory, but the details can be very hardware specific (cache lines, memory barriers etc). But also jvm specific, (the hotspot server compiler might hoist non volatile variables for example) and it imposes limits on reordering instructions for possible performance gains as well



回答2:

The explanation is on the next page (emphasis by me):

What this variable does is to ensure that field is read only once in the common case where it’s already initialized. While not strictly necessary, this may improve performance and is more elegant by the standards applied to low-level concurrent programming. On my machine, the method above is about 25 percent faster than the obvious version without a local variable.

For reference, the quote is from p. 284 of Item 71: Use lazy initialization judiciously in Effective Java 2nd Edition.

Update: the difference between reading a local vs a volatile variable is that the former may be optimized better. Volatile variables can't be stored in registers or caches, nor memory operations on them reordered. Moreover, reading a volatile variable may trigger memory synchronization between different threads.

See Java Concurrency in Practice, section 3.1.4: Volatile Variables for more details.