问题:

I have a custom widget and it needs to launch a MessageDialog and in order for me to put that message dialog on top of the window my widget is in then I need access to the parent gtk.window. Is there a way to get the parent GTK window? Thanks

回答1:

The GTK docs suggest:

   GtkWidget *toplevel = gtk_widget_get_toplevel (widget);
   if (gtk_widget_is_toplevel (toplevel))
     {
       /* Perform action on toplevel. */
     }

get_toplevel will return the topmost widget you're inside, whether or not it's a window, thus the is_toplevel check. Yeah something is mis-named since the code above does a "get_toplevel()" then an immediate "is_toplevel()" (most likely, get_toplevel() should be called something else).

回答2:

In pygtk, you can get the toplevel like toplevel = mywidget.get_toplevel() then feed toplevel directly to gtk.MessageDialog()

回答3:

Though gtk_widget_get_toplevel should work, you may also give a try to the code below. It should get the parent gtk window for the given widget and print it's title.

GdkWindow *gtk_window = gtk_widget_get_parent_window(widget);
GtkWindow *parent = NULL;
gdk_window_get_user_data(gtk_window, (gpointer *)&parent);
g_print("%s\n", gtk_window_get_title(parent));

hope this helps, regards