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问题:
Typically, I\'ve seen people use the class literal like this:
Class<Foo> cls = Foo.class;
But what if the type is generic, e.g. List? This works fine, but has a warning since List should be parameterized:
Class<List> cls = List.class
So why not add a <?>
? Well, this causes a type mismatch error:
Class<List<?>> cls = List.class
I figured something like this would work, but this is just a plain ol\' syntax error:
Class<List<Foo>> cls = List<Foo>.class
How can I get a Class<List<Foo>>
statically, e.g. using the class literal?
I could use @SuppressWarnings(\"unchecked\")
to get rid of the warnings caused by the non-parameterized use of List in the first example, Class<List> cls = List.class
, but I\'d rather not.
Any suggestions?
回答1:
You can\'t due to type erasure.
Java generics are little more than syntactic sugar for Object casts. To demonstrate:
List<Integer> list1 = new ArrayList<Integer>();
List<String> list2 = (List<String>)list1;
list2.add(\"foo\"); // perfectly legal
The only instance where generic type information is retained at runtime is with Field.getGenericType()
if interrogating a class\'s members via reflection.
All of this is why Object.getClass()
has this signature:
public final native Class<?> getClass();
The important part being Class<?>
.
To put it another way, from the Java Generics FAQ:
Why is there no class literal for concrete parameterized types?
Because parameterized type has no exact runtime type representation.
A class literal denotes a Class
object that represents a given type.
For instance, the class literal
String.class
denotes the Class
object that represents the type
String
and is identical to the
Class
object that is returned when
method getClass
is invoked on a
String
object. A class literal can
be used for runtime type checks and
for reflection.
Parameterized types lose their type
arguments when they are translated to
byte code during compilation in a
process called type erasure . As a
side effect of type erasure, all
instantiations of a generic type share
the same runtime representation,
namely that of the corresponding raw
type . In other words, parameterized
types do not have type representation
of their own. Consequently, there is
no point in forming class literals
such as List<String>.class
,
List<Long>.class
and List<?>.class
, since no such Class
objects exist.
Only the raw type List
has a Class
object that represents its runtime
type. It is referred to as
List.class
.
回答2:
There are no Class literals for parameterized types, however there are Type objects that correctly define these types.
See java.lang.reflect.ParameterizedType
- http://java.sun.com/j2se/1.5.0/docs/api/java/lang/reflect/ParameterizedType.html
Google\'s Gson library defines a TypeToken class that allows to simply generate parameterized types and uses it to spec json objects with complex parameterized types in a generic friendly way. In your example you would use:
Type typeOfListOfFoo = new TypeToken<List<Foo>>(){}.getType()
I intended to post links to the TypeToken and Gson classes javadoc but Stack Overflow won\'t let me post more than one link since I\'m a new user, you can easily find them using Google search
回答3:
You can manage it with a double cast :
@SuppressWarnings(\"unchecked\")
Class<List<Foo>> cls = (Class<List<Foo>>)(Object)List.class
回答4:
To expound on cletus\' answer, at runtime all record of the generic types is removed. Generics are processed only in the compiler and are used to provide additional type safety. They are really just shorthand that allows the compiler to insert typecasts at the appropriate places. For example, previously you\'d have to do the following:
List x = new ArrayList();
x.add(new SomeClass());
Iterator i = x.iterator();
SomeClass z = (SomeClass) i.next();
becomes
List<SomeClass> x = new ArrayList<SomeClass>();
x.add(new SomeClass());
Iterator<SomeClass> i = x.iterator();
SomeClass z = i.next();
This allows the compiler to check your code at compile-time, but at runtime it still looks like the first example.
回答5:
Well as we all know that it gets erased. But it can be known under some circumstances where the type is explicitly mentioned in the class hierarchy:
import java.lang.reflect.*;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.LinkedHashMap;
import java.util.Map;
import java.util.stream.Collectors;
public abstract class CaptureType<T> {
/**
* {@link java.lang.reflect.Type} object of the corresponding generic type. This method is useful to obtain every kind of information (including annotations) of the generic type.
*
* @return Type object. null if type could not be obtained (This happens in case of generic type whose information cant be obtained using Reflection). Please refer documentation of {@link com.types.CaptureType}
*/
public Type getTypeParam() {
Class<?> bottom = getClass();
Map<TypeVariable<?>, Type> reifyMap = new LinkedHashMap<>();
for (; ; ) {
Type genericSuper = bottom.getGenericSuperclass();
if (!(genericSuper instanceof Class)) {
ParameterizedType generic = (ParameterizedType) genericSuper;
Class<?> actualClaz = (Class<?>) generic.getRawType();
TypeVariable<? extends Class<?>>[] typeParameters = actualClaz.getTypeParameters();
Type[] reified = generic.getActualTypeArguments();
assert (typeParameters.length != 0);
for (int i = 0; i < typeParameters.length; i++) {
reifyMap.put(typeParameters[i], reified[i]);
}
}
if (bottom.getSuperclass().equals(CaptureType.class)) {
bottom = bottom.getSuperclass();
break;
}
bottom = bottom.getSuperclass();
}
TypeVariable<?> var = bottom.getTypeParameters()[0];
while (true) {
Type type = reifyMap.get(var);
if (type instanceof TypeVariable) {
var = (TypeVariable<?>) type;
} else {
return type;
}
}
}
/**
* Returns the raw type of the generic type.
* <p>For example in case of {@code CaptureType<String>}, it would return {@code Class<String>}</p>
* For more comprehensive examples, go through javadocs of {@link com.types.CaptureType}
*
* @return Class object
* @throws java.lang.RuntimeException If the type information cant be obtained. Refer documentation of {@link com.types.CaptureType}
* @see com.types.CaptureType
*/
public Class<T> getRawType() {
Type typeParam = getTypeParam();
if (typeParam != null)
return getClass(typeParam);
else throw new RuntimeException(\"Could not obtain type information\");
}
/**
* Gets the {@link java.lang.Class} object of the argument type.
* <p>If the type is an {@link java.lang.reflect.ParameterizedType}, then it returns its {@link java.lang.reflect.ParameterizedType#getRawType()}</p>
*
* @param type The type
* @param <A> type of class object expected
* @return The Class<A> object of the type
* @throws java.lang.RuntimeException If the type is a {@link java.lang.reflect.TypeVariable}. In such cases, it is impossible to obtain the Class object
*/
public static <A> Class<A> getClass(Type type) {
if (type instanceof GenericArrayType) {
Type componentType = ((GenericArrayType) type).getGenericComponentType();
Class<?> componentClass = getClass(componentType);
if (componentClass != null) {
return (Class<A>) Array.newInstance(componentClass, 0).getClass();
} else throw new UnsupportedOperationException(\"Unknown class: \" + type.getClass());
} else if (type instanceof Class) {
Class claz = (Class) type;
return claz;
} else if (type instanceof ParameterizedType) {
return getClass(((ParameterizedType) type).getRawType());
} else if (type instanceof TypeVariable) {
throw new RuntimeException(\"The type signature is erased. The type class cant be known by using reflection\");
} else throw new UnsupportedOperationException(\"Unknown class: \" + type.getClass());
}
/**
* This method is the preferred method of usage in case of complex generic types.
* <p>It returns {@link com.types.TypeADT} object which contains nested information of the type parameters</p>
*
* @return TypeADT object
* @throws java.lang.RuntimeException If the type information cant be obtained. Refer documentation of {@link com.types.CaptureType}
*/
public TypeADT getParamADT() {
return recursiveADT(getTypeParam());
}
private TypeADT recursiveADT(Type type) {
if (type instanceof Class) {
return new TypeADT((Class<?>) type, null);
} else if (type instanceof ParameterizedType) {
ArrayList<TypeADT> generic = new ArrayList<>();
ParameterizedType type1 = (ParameterizedType) type;
return new TypeADT((Class<?>) type1.getRawType(),
Arrays.stream(type1.getActualTypeArguments()).map(x -> recursiveADT(x)).collect(Collectors.toList()));
} else throw new UnsupportedOperationException();
}
}
public class TypeADT {
private final Class<?> reify;
private final List<TypeADT> parametrized;
TypeADT(Class<?> reify, List<TypeADT> parametrized) {
this.reify = reify;
this.parametrized = parametrized;
}
public Class<?> getRawType() {
return reify;
}
public List<TypeADT> getParameters() {
return parametrized;
}
}
And now you can do things like:
static void test1() {
CaptureType<String> t1 = new CaptureType<String>() {
};
equals(t1.getRawType(), String.class);
}
static void test2() {
CaptureType<List<String>> t1 = new CaptureType<List<String>>() {
};
equals(t1.getRawType(), List.class);
equals(t1.getParamADT().getParameters().get(0).getRawType(), String.class);
}
private static void test3() {
CaptureType<List<List<String>>> t1 = new CaptureType<List<List<String>>>() {
};
equals(t1.getParamADT().getRawType(), List.class);
equals(t1.getParamADT().getParameters().get(0).getRawType(), List.class);
}
static class Test4 extends CaptureType<List<String>> {
}
static void test4() {
Test4 test4 = new Test4();
equals(test4.getParamADT().getRawType(), List.class);
}
static class PreTest5<S> extends CaptureType<Integer> {
}
static class Test5 extends PreTest5<Integer> {
}
static void test5() {
Test5 test5 = new Test5();
equals(test5.getTypeParam(), Integer.class);
}
static class PreTest6<S> extends CaptureType<S> {
}
static class Test6 extends PreTest6<Integer> {
}
static void test6() {
Test6 test6 = new Test6();
equals(test6.getTypeParam(), Integer.class);
}
class X<T> extends CaptureType<T> {
}
class Y<A, B> extends X<B> {
}
class Z<Q> extends Y<Q, Map<Integer, List<List<List<Integer>>>>> {
}
void test7(){
Z<String> z = new Z<>();
TypeADT param = z.getParamADT();
equals(param.getRawType(), Map.class);
List<TypeADT> parameters = param.getParameters();
equals(parameters.get(0).getRawType(), Integer.class);
equals(parameters.get(1).getRawType(), List.class);
equals(parameters.get(1).getParameters().get(0).getRawType(), List.class);
equals(parameters.get(1).getParameters().get(0).getParameters().get(0).getRawType(), List.class);
equals(parameters.get(1).getParameters().get(0).getParameters().get(0).getParameters().get(0).getRawType(), Integer.class);
}
static void test8() throws IllegalAccessException, InstantiationException {
CaptureType<int[]> type = new CaptureType<int[]>() {
};
equals(type.getRawType(), int[].class);
}
static void test9(){
CaptureType<String[]> type = new CaptureType<String[]>() {
};
equals(type.getRawType(), String[].class);
}
static class SomeClass<T> extends CaptureType<T>{}
static void test10(){
SomeClass<String> claz = new SomeClass<>();
try{
claz.getRawType();
throw new RuntimeException(\"Shouldnt come here\");
}catch (RuntimeException ex){
}
}
static void equals(Object a, Object b) {
if (!a.equals(b)) {
throw new RuntimeException(\"Test failed. \" + a + \" != \" + b);
}
}
More info here. But again, it is almost impossible to retrieve for:
class SomeClass<T> extends CaptureType<T>{}
SomeClass<String> claz = new SomeClass<>();
where it gets erased.
回答6:
Due to the exposed fact that Class literals doesn\'t have generic type information, I think you should assume that it will be impossible to get rid of all the warnings. In a way, using Class<Something>
is the same as using a collection without specifying the generic type. The best I could come out with was:
private <C extends A<C>> List<C> getList(Class<C> cls) {
List<C> res = new ArrayList<C>();
// \"snip\"... some stuff happening in here, using cls
return res;
}
public <C extends A<C>> List<A<C>> getList() {
return getList(A.class);
}
回答7:
You could use a helper method to get rid of @SuppressWarnings(\"unchecked\")
all over a class.
@SuppressWarnings(\"unchecked\")
private static <T> Class<T> generify(Class<?> cls) {
return (Class<T>)cls;
}
Then you could write
Class<List<Foo>> cls = generify(List.class);
Other usage examples are
Class<Map<String, Integer>> cls;
cls = generify(Map.class);
cls = TheClass.<Map<String, Integer>>generify(Map.class);
funWithTypeParam(generify(Map.class));
public void funWithTypeParam(Class<Map<String, Integer>> cls) {
}
However, since it is rarely really useful, and the usage of the method defeats the compiler\'s type checking, I would not recommend to implement it in a place where it is publicly accessible.