问题:

import argparse

parser = argparse.ArgumentParser(description='sort given numbers')
parser.add_argument('-s', nargs = '+', type = int)
args = parser.parse_args()
print(args)

On command line when I run the command

python3 file_name.py -s 9 8 76

It prints Namespace(s=[9, 8, 76]).

How can I access the list [9, 8, 76]? What is the namespace object. Where can I learn more about it?

回答1:

The documentation for argparse.Namespace can be found here.
You can access the s attribute by doing args.s.
If you'd like to access this as a dictionary, you can do vars(args), which means you can also do vars(args)['s']

回答2:

It is the result object that argparse returns; the items named are attributes:

print(args.s)

This is a very simple object, deliberately so. Your parsed arguments are attributes on this object (with the name determined by the long option, or if set, the dest argument).

回答3:

you can access as args.s , NameSpace class is deliberately simple, just an object subclass with a readable string representation. If you prefer to have dict-like view of the attributes, you can use the standard Python idiom, vars(). Source