I am using mongo php library, and trying to insert some old data into mongodb. I used insertMany() method and pass a huge array of document, that may have duplicate documents on unique indexes.
Lets say I have a users collection and have these indexes:
[
{
"v" : 1,
"key" : {
"_id" : 1
},
"name" : "_id_",
"ns" : "test.users"
},
{
"v" : 1,
"unique" : true,
"key" : {
"email" : 1
},
"name" : "shop_id_1_title_1",
"ns" : "test.users"
}
]
If there's a duplicate document, MongoDB\Driver\Exception\BulkWriteException would raise and stop the process. I want to find a way to ignore inserting duplicate documents (and also preventing the exception from raise) and continue inserting other documents.
I found in php.net documentation a flag called continueOnError that do the trick but it seems that it's not working with this library.
The example from php.net:
<?php
$con = new Mongo;
$db = $con->demo;
$doc1 = array(
'_id' => new MongoId('4cb4ab6d7addf98506010001'),
'id' => 1,
'desc' => "ONE",
);
$doc2 = array(
'_id' => new MongoId('4cb4ab6d7addf98506010002'),
'id' => 2,
'desc' => "TWO",
);
$doc3 = array(
'_id' => new MongoId('4cb4ab6d7addf98506010002'), // same _id as above
'id' => 3,
'desc' => "THREE",
);
$doc4 = array(
'_id' => new MongoId('4cb4ab6d7addf98506010004'),
'id' => 4,
'desc' => "FOUR",
);
$c = $db->selectCollection('c');
$c->batchInsert(
array($doc1, $doc2, $doc3, $doc4),
array('continueOnError' => true)
);
And the way I tried to use the flag with mongo php library:
<?php
$users = (new MongoDB\Client)->test->users
$collection->insertMany([
[
'username' => 'admin',
'email' => 'admin@example.com',
'name' => 'Admin User',
],
[
'username' => 'test',
'email' => 'test@example.com',
'name' => 'Test User',
],
[
'username' => 'test 2',
'email' => 'test@example.com',
'name' => 'Test User 2',
],
],
[
'continueOnError' => true // This option is not working
]);
The code above still raise the exception, and seems not to work. Is there other option flag or is there any way to do this?
