Hi im using jqplot graph. I need to hide the Circular points that are currently displayed on the plot chart for each value in the array except the last point.
I use the following code to display the chart. I used "show marker : false" option, but it hides all circular in the graph. Please help me how to show only one circular point in the graph.
<div id="chart2"></div>
var line2 = [['2012-10-02', 20],['2012-10-03', 45],['2012-10-04', 35],['2012-10-05', 32],['2012-10-06', 30],['2012-10-07', 25]];
var plot1 = $.jqplot('chart2', [line2], {
seriesDefaults: {
showMarker: false
},
axes:{
xaxis:{
renderer:$.jqplot.DateAxisRenderer,
labelRenderer: $.jqplot.CanvasAxisLabelRenderer,
tickRenderer: $.jqplot.CanvasAxisTickRenderer,
tickOptions: {
angle: -90,
formatString: '%m/%d/%Y'
},
}
},
yaxis: {
labelRenderer: $.jqplot.CanvasAxisLabelRenderer
},
highlighter: {
show: true
},
cursor: {
show: false
}
});
I want to achieve the below screen as my output. please help me how this could be done. Any help will be appreciated.