Can I use destructuring somehow inside an if state

问题:

is there a way I could do something like this ?

if({color, size, shape} = this.props){
  console.log('Received all props!');
} else {
  console.log('There are some missing props');
}

I want to know if I received all needed data through my Component's props, and if not then throw an error.

It's for creating reusable components.

回答1:

You could use default values:

function missing(prop) {
    throw new TypeError(`there is a missing ${prop} property`);
}

…
try {
  const {
    color = missing("color"),
    size = missing("size"),
    shape = missing("shape"),
  } = this.props;
  // use color, size, shape here
  console.log("Received all props!");
} catch(err) {
  console.log(err.message);
}

To use an if statement, no you cannot use destructuring to produce a boolean whether all properties are there. Rather do something usual as

if ("color" in this.props && "size" in this.props && "shape" in this.props) {
  console.log('Received all props!');
} else {
  console.log('There are some missing props');
}

(or better yet, check for the type of the value that you expected)