Appending/concatenating two IEnumerable sequences

问题:

I have two sets of datarows. They are each IEnumerable. I want to append/concatenate these two lists into one list. I'm sure this is doable. I don't want to do a for loop and noticed that there is a Union method and a Join method on the two Lists. Any ideas?

回答1:

Assuming your objects are of the same type, you can use either Union or Concat. Note that, like the SQL UNION keyword, the Union operation will ensure that duplicates are eliminated, whereas Concat (like UNION ALL) will simply add the second list to the end of the first.

IEnumerable<T> first = ...;
IEnumerable<T> second = ...;

IEnumerable<T> combined = first.Concat(second);

or

IEnumerable<T> combined = first.Union(second);

If they are of different types, then you'll have to Select them into something common. For example:

IEnumerable<TOne> first = ...;
IEnumerable<TTwo> second = ...;

IEnumerable<T> combined = first.Select(f => ConvertToT(f)).Concat(
                          second.Select(s => ConvertToT(s)));

Where ConvertToT(TOne f) and ConvertToT(TTwo s) represent an operation that somehow converts an instance of TOne (and TTwo, respectively) into an instance of T.

回答2:

I just encountered a similar situation where I need to concatenate multiple sequences.

Naturally searched for existing solutions on Google/StackOverflow, however did not find anything the did not evaluate the enumerable, e.g. convert to array then use Array.Copy() etc., so I wrote an extension and static utiltiy method called ConcatMultiple.

Hope this helps anyone that needs to do the same.

/// <summary>
/// Concatenates multiple sequences
/// </summary>
/// <typeparam name="TSource">The type of the elements of the input sequences.</typeparam>
/// <param name="first">The first sequence to concatenate.</param>
/// <param name="source">The other sequences to concatenate.</param>
/// <returns></returns>
public static IEnumerable<TSource> ConcatMultiple<TSource>(this IEnumerable<TSource> first, params IEnumerable<TSource>[] source)
{
    if (first == null)
        throw new ArgumentNullException("first");

    if (source.Any(x => (x == null)))
        throw new ArgumentNullException("source");

    return ConcatIterator<TSource>(source);
}

private static IEnumerable<TSource> ConcatIterator<TSource>(IEnumerable<TSource> first, params IEnumerable<TSource>[] source)
{
    foreach (var iteratorVariable in first)
        yield return iteratorVariable;

    foreach (var enumerable in source)
    {
        foreach (var iteratorVariable in enumerable)
            yield return iteratorVariable;
    }
}

/// <summary>
/// Concatenates multiple sequences
/// </summary>
/// <typeparam name="TSource">The type of the elements of the input sequences.</typeparam>        
/// <param name="source">The sequences to concatenate.</param>
/// <returns></returns>
public static IEnumerable<TSource> ConcatMultiple<TSource>(params IEnumerable<TSource>[] source)
{
    if (source.Any(x => (x == null)))
        throw new ArgumentNullException("source");

    return ConcatIterator<TSource>(source);
}

private static IEnumerable<TSource> ConcatIterator<TSource>(params IEnumerable<TSource>[] source)
{
    foreach (var enumerable in source)
    {
        foreach (var iteratorVariable in enumerable)
            yield return iteratorVariable;
    }
}

回答3:

The Join method is like a SQL join, where the list are cross referenced based upon a condition, it isn't a string concatenation or Adding to a list. The Union method does do what you want, as does the Concat method, but both are LAZY evaluations, and have the requirement the parameters be non-null. They return either a ConcatIterator or a UnionIterator, and if called repeatedly this could cause problems. Eager evaluation results in different behavior, if that is what you want, then an extension method like the below could be used.

public static IEnumerable<T> myEagerConcat<T>(this IEnumerable<T> first,
                                                   IEnumerable<T> second)
{
    return (first ?? Enumerable.Empty<T>()).Concat(
           (second ?? Enumerable.Empty<T>())).ToList();
}