Include date in nginx log file name

问题:

I am running nginx 1.15.6 and I am trying to include the current date in the nginx log file name.

Some thing like this: access_log /var/log/nginx/access.2018.11.07.log main;

Anyone know how to do this?

回答1:

This is what I ended up using and it works perfectly:

map $time_iso8601 $year {
    default '0000';
    "~^(\d{4})-(\d{2})-(\d{2})" $1;
}
map $time_iso8601 $month {
    default '00';
    "~^(\d{4})-(\d{2})-(\d{2})" $2;
}
map $time_iso8601 $day {
    default '00';
    "~^(\d{4})-(\d{2})-(\d{2})" $3;
}

access_log  /var/log/nginx/access.$year-$month-$day.log  apm_json;

回答2:

server {

    if ($time_iso8601 ~ "^(\d{4})-(\d{2})-(\d{2})") {
        set $year $1;
        set $month $2;
        set $day $3;
    }

    access_log /var/log/nginx/$year-$month-$day-access.log;

回答3:

IF is Evil, in Nginx configurations. A detailed description as to why can be found at Nginx: If is Evil.

A better solution would be to use a map for logging dates.

Example below.

map $time_iso8601 $year {
    default             'date';
    '~^(?<yyyy>\d{4})-'     $yyyy;
}
map $time_iso8601 $month {
    default             'not';
    '~^\d{4}-(?<mm>\d{2})-'     $mm;
}
map $time_iso8601 $day {
    default             'found';
    '~^\d{4}-\d{2}-(?<dd>\d{2})'    $dd;
}
map $time_iso8601 $logfile_date {
    default                         'date-not-found';
    '~^(?<year>\d{4})-(?<month>\d{2})-(?<day>\d{2})'    $year-$month-$day;
}

access_log c:/tools/nginx/logs/$logfile_date.access.log;