from subprocess import PIPE,Popen
p = Popen("ls -l",shell=True,stderr=PIPE,stdout=PIPE)
(out,err) = p.communicate()
print(out, err)
In above Popen call, if I remove stdout=PIPE
, I am getting newline after every listing by ls -l
in output. But if use stdout=PIPE
, I get \n
displayed, rather than newline, as below
b'total 67092\n-rw-r--r-- 1 root root 171 May 27 09:08 new.py\n-rw-r--r-- 1
root root 74 May 12 18:14 abcd.conf\n-rwxr-xr-x 1 root root 5948 May 13 13:21 abxyz.sh\ndrwxr-xr-x 2 root root 4096 May 13
12:39 log\ndrwxrwxrwx 3 root root 4096 May 14 16:02
newpy\n-rw-r--r-- 1 root root 134 May 27 10:13
pipe.py\n-rw-r--r-- 1 root root 155 May 27 10:07
proc.py\ndrwxrwxrwx 3 root root 4096 May 14 14:29 py\ndrwxr-xr-x
16 1000 1000\n' b''
How does PIPE
exactly works in case of subprocess.Popen
? Why do we need it? I got proper output without using it also? Are we using this for getting both stderr, stdout?